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denis23 [38]
4 years ago
11

10 molecules SO2 to moles

Chemistry
1 answer:
cluponka [151]4 years ago
3 0

Answer:

1.66 * 10^-23 moles

Explanation:

If you follow dimensional analysis, molecules to moles is 10 molecules divided by 6.022 times 10 to the 23rd and that gives you your answer

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According to the periodic trend, which of the following is most likely to have the lowest electronegativity? F N Be Li
11111nata11111 [884]
Lithium. Electronegativty increases across the periodic table and increases down the periodic table.
5 0
4 years ago
Read 2 more answers
Which intermolecular force is characteristic of compounds with low molar mass, which are liquids at room temperature and have re
eduard

Answer:

Hydrogen bonds.

Explanation:

The intermolecular forces are the forces that are presented between molecules in a substance. As higher is the force, as closer are the molecules, and more difficult will be to separate them.

Because of that, the solids have stronger forces than the liquids, which have stronger forces than the gases. Also, as strong the force, as higher will be the boiling point.

The ionic bond is the strongest and it's presented at ionic compounds, which are solids at room temperature and have high boiling points.

The covalent bonds are presented in the molecules and are formed when atoms share pairs of electrons. Between these molecules, the forces can be London forces, dipole-dipole forces, or hydrogen bonds.

The London forces are the weaker, they are presented at the nonpolar molecules, so it's easy to boil it. For a compound with low molar mass and London forces, it'll probably be at the gas phase at room temperature.

The dipole-dipole forces are presented at the polar molecules, and it's strong than the London forces. And the hydrogen bonds are a specific type of dipole-dipole forces, which is stronger and is formed between hydrogen and F, O, or N.

Because hydrogen has a low molar mass (1 g/mol), the compounds formed by it intends to have a low molar mass. So, to be liquid at room temperature, low mass, and high boiling point, it's more probable that the compound has hydrogen bonds.

6 0
3 years ago
When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?
AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S       →       Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

                      FeCl₃          :          Fe₂S₃

                       2                :            1

                      20               :          1/2 ×20 = 10

                      FeCl₃          :            HCl

                       2                :              6

                      20               :          6/2 ×20 = 60

                      H₂S             :          Fe₂S₃

                       3                :            1

                      15               :          1/3 ×15 = 5

                      H₂S            :            HCl

                       3                :              6

                      15                :          6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

 

5 0
3 years ago
A quantity of HCL ( 1.5*10⁻³ M) is added to water at 25°C to increase the hydrogen ion concentration from 1*10⁻⁷ to 1.5* 10⁻³ mo
algol13
Do you have a paper?
3 0
3 years ago
If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?
Fantom [35]

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

PV=nRT\\\\P=\dfrac{nRT}{V}

R = 0.0821 L-atm/mol-K

Put all the values,

P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L

So, the pressure of the gas is 27.07 atm.

8 0
3 years ago
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