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MrRissso [65]
3 years ago
10

Which of the following alcohols will give a positive chromic acid test?

Chemistry
1 answer:
Sindrei [870]3 years ago
3 0
The answer is both B and C

positive chromic acid test is indicated by disappearance of orange colour from chromic ions and appearance of blue-green color from Chromium (iii) ion (reduction of chromium ion from CrO4 - to Cr3+)

positive chromic test indicated functional groups that can be oxidized.

cyclohexanol can be oxidized to become cyclohexanone

and pentan-3-ol can be oxidized to become pentan-3-one

hence both B and C will show positive chromic acid test

A) tert butanol although contains alcohol functional group, cannot be further oxidized as it is a tertiary alcohol

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12%

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In the biosphere, prey represent a food source for predators. An increase in the population of prey means more food for predator
mote1985 [20]
<h2>Answer:</h2>

An increase in the population of prey means more food for predators, which will<u> increase</u> the predators' population. As a result, many more prey will be hunted, causing the prey population to<u> decrease.</u> In response, the predator population will <u>decrease</u>, resulting in an increase in the prey population.

<h3>Explanation:</h3>

The feedback loop is control of the system containing the prey and predator.

In this loop, the population of predator is directly proportional to prey but the population of prey is inversely proportional to a predators population.

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A boundary between air masses that don't move possibly causing rain for several days.
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3 years ago
How many liters of water vapor can be produced if 108 grams of methane gas (CH4) are combusted at 312 K and 0.98 atm? Show all w
MA_775_DIABLO [31]

Answer:

Approximately 352 liters of water vapor will be produced.

Assumption: the water vapor here behaves like an ideal gas.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Carbon: 12.011;
  • Hydrogen: 1.008.

Burning methane \rm CH_4 in excess oxygen will produce carbon dioxide and water. The balanced equation will be

\rm CH_4\; (g) + 2\; O_2\;(g) \to CO_2\;(g) + 2\; H_2O\;(g).

Hint: start by assign "1" to methane while balancing this equation.

How many moles of molecules in 108 gram of methane?

Molar mass of methane:

M(\rm CH_4) = 12.011 + 4\time 1.008 =16.043\;g\cdot mol^{-1}.

\displaystyle n(\rm CH_4) = \frac{m}{M} = \frac{108}{16.043} = 6.73191\;mol.

How many moles of water molecules will be produced?

Consider the ratio between the coefficient in front of water and that in front of methane in the equation:

\displaystyle \frac{n(\mathrm{H_2O})}{n(\mathrm{CH_4})} = 2.

\displaystyle n(\mathrm{H_2O}) = n(\mathrm{CH_4})\cdot \frac{n(\mathrm{H_2O})}{n(\mathrm{CH_4})} = \rm 2\times 6.73191\;mol = 13.4638\;mol.

Assume that water vapor here behaves like an ideal gas.

Ideal gas constant in liters and \rm atm:

R \rm \approx 0.0820573\;L\cdot atm \cdot K^{-1}\cdot mol^{-1}. (NIST.)

Make sure that the temperature here is in degrees Kelvins.

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P} \\ &= \rm \frac{13.4638\;mol\times 0.0820573\;L\cdot atm \cdot K^{-1}\cdot mol^{-1}\times 312\; K}{0.98\; atm}\\ &\rm \approx 352\; L\end{aligned}.

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Answer:

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Explanation:

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