To be able to solve this problem, we must be given the
balanced chemical equation:
3A + 5B + 1C ---> 2D + 1E
Our reactant A is called the limiting reactant because it
is limited in amount which is only 6 moles. So we based our calculation on that
reactant alone.
From stoichiometry, we have 1 mole of E for every 3 moles
of A, therefore:
moles E = 6 moles A * (1 mole E / 3 moles A)
moles E = 2 moles
A : water
I think , I hope it’s correct
Answer:
The enthalpy change per mole of Mg is (ΔH) = 460 kj mol⁻¹
Explanation:
the total volume of the solution is
100 ml, its mass is (100 ml)(1.0 g ml⁻¹) = 100 g (Density of water 1 g ml⁻¹)
The temperature change is ΔT = 11.1 ∘C
Heat of reaction = Cs × m × ∆T
= (4.18 Jg⁻¹ ∘C⁻¹)(100 g)(11.1 ∘C)
= 4639.8 j = 4.6 kJ
Because the process occurs at constant pressure, ΔH = qP = 4.6 kJ
To express the enthalpy change on a molar basis
Mole of Mg = = 0.01 mol
Thus, the enthalpy change per mole of Mg is ΔH = = 460 kj mol⁻¹
If you are given only delta G? Not enough information, unless you also have a big chart of a ton of heats of formation and other stuff
D. The average kinetic energy increases, and the particles collide more frequently.
Explanation:
When the temperature of a gas is increased, the average kinetic energy increases and the particles collide more frequently with one another and the walls of the container.
- The temperature of a gas is a measure of the average kinetic energy of the molecules.
- When temperature increases, the frequency of ordinary and effective collision increases per unit time.
Learn more:
Kinetic energy of gases brainly.com/question/7966903
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