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saveliy_v [14]
2 years ago
13

The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

Chemistry
2 answers:
marshall27 [118]2 years ago
8 0
The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed. This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
ruslelena [56]2 years ago
4 0

Answer:

Answer is 0.0136.

Explanation:

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Since silver and gold are both shiny, rare and do not corrode, they are ideal materials for making... what?
LUCKY_DIMON [66]

Answer:

Jewelry

Explanation:

Gold and silver  are metals which are malleable, ductile, and lustrous. Also they are noble metals. since they are noble metals they are not affected by acid, oxygen, atmosphere and etc. hence gold and silver are used or suitable for making jewlery.

4 0
3 years ago
How much energy is required to convert 100.0 g of water completely<br> to steam?
Brrunno [24]

Answer:

<u>225.6 kJ</u>, <em>assuming the water is already at 100 °C</em>

Explanation:

The correct answer to this question will depend on the initial temperature of the water to which heat is added to produce steam.  Energy is required to raise the water temperature to 100°C.  At that point, an energy of vaporization is needed to convert liquid water at 100 °C to water vapor at 100°C.  The heat of vaporization for water is 2256.4 kJ/kg.  The energy required to bring 100g of water from a lower temperature to 100°C is calculated at 4.186 J/g°C.  We don't know the starting temperature, so this step cannot be calculated.

<em><u>Assuming</u></em> that we are already at 100 °C, we can calculate the heat required for vaporization:

(100.0g)(1000.0g/1 kg)(2256.4 kJ/kg) = 225.6 kJ for 100 grams water.

3 0
2 years ago
What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?
ArbitrLikvidat [17]
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


8 0
3 years ago
Paul placed an ice cube into a beaker on a hot plate. The ice cube changed from a solid to a liquid and then to a gas. During th
faltersainse [42]
One thing that does not change is the chemical composition of water, which is still H2O. And maybe mass, if all of the particles remain inside the beaker, which was never mentioned in the question so I am not sure.
6 0
3 years ago
Read 2 more answers
HELP PLEASE!
tia_tia [17]

Vocabulary. Balanced chemical equation: A chemical equation in which the number of each type of atom is equal on the two sides of the equation.

Hope I helped! (´▽`)

__________________________________________________________

単語。平衡化学反応式:各タイプの原子の数が方程式の両側で等しい化学反応式。

私が助けてくれたらいいのに!(´▽`)

5 0
3 years ago
Read 2 more answers
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