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3 years ago

Put the following stages of star formation into the proper sequence from earliest to latest:

Physics

1 answer:

BaLLatris [955]3 years ago

5 0

C → A → E → D → F → H → G → I → B

Explanation:

Put into the proper order, the following are the stages of star formation from earliest to latest:

Massive, rotating, amorphous interstellar cloud collapses and fragments → Infalling material forms a hot and luminous protostar at the center of the disk → Gravitational contraction causes protostar to shrink and heat as it descends the Hyashi track → As the shrinking protostar heats up, hydrogen is ionized and a magnetic field forms → Magnetic bipolar outflows begin along rotation axis as the magnetic field forms → As bipolar outflows become stronger, powerful T-Tauri winds start clearing the nebula before the onset of nuclear fusion → Shrinking cloud collapses into a flat disk shape → Onset of nuclear fusion in the core occurs around 15 million K → Newly-formed star settles onto the Main Sequence

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In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward

Vladimir79 [104]

Answer:

The answer is " $1.01 \times 10^{-13}$ "

Explanation:

Using the law of conservation for energy. Equating the kinetic energy to the potential energy.

$KE=U=\frac{kqq'}{r}\\\\$

Calculating the closest distance:

$\to r=\frac{kqq'}{KE}\\\\$

$=\frac{k(2e)(79e)}{KE}\\\\=\frac{k(2)(79)e^2}{KE}\\\\=\frac{9.0\times 10^9 \ N \cdot \frac{m^2}{c}(2)(79)(1.6 \times10^{-19} \ C)^2}{(2.25\ meV) (\frac{1.6 \times 10^{-13} \ J}{1 \ MeV})}\\\\$

$=\frac{9.0\times 10^9 \times 2\times 79\times 1.6 \times10^{-19}\times 1.6 \times10^{-19} }{(2.25 \times 1.6 \times 10^{-13}) }\\\\=\frac{3,640.32\times 10^{-29}}{3.6 \times 10^{-13} }\\\\=\frac{3,640.32}{3.6} \times 10^{-16}\\\\=1011.2 \times 10^{-16}\\\\=1.01 \times 10^{-13}$

5 0

3 years ago

Fill in a T/F answer for each statement below. If false, correct the statement to make it true.:

grandymaker [24]

Answer:

Explanation:

Let's answer these statements

.1) True. This is the law of reflection.

.2) False. The speed of light depends on the index of refraction n = c / v

v = c / n

.3) True. The frequency creates a forced oscillation, whereby the atoms re-emit at the same incident frequency

.4) False. The index of refraction is a measure of the ratio of the speed of light in a vacuum and the material environment, the ability to change the trajectory is given by the law of refraction

.5) True. True due to the change in beam trajectory due to the law of refraction

.6 False. The phenomenon occurs when you pass from a medium with a higher index to one with a lower ratio, because the refracted beam separates from the normal

.7) True.

.8) False so that the lightning approach is valid Lam >> d,

.9) True.

3 0

3 years ago

The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista

noname [10]

To convert km to AU, we divide 225,000,000 km by the factor of 1.5 x 10^8 = 150,000,000 km. This gives us 225,000,000 / 150,000,000 = 1.5 AU. Therefore, the distance between Earth and Mars in AU is 1.5 AU.
The AU is not equivalent to a light-year. A light-year is equivalent to around 9.5 x 10^12 kilometers.

4 0

3 years ago

Un objeto se suelta desde determinada altura y emplea un tiempo t en caer al suelo. Si se cuadruplica la altura desde la cual se

blondinia [14]

When an object falls from a h height, you should work with the uniformly accelerated linear movement equations:

y=½*a*t²+Vo*t+yo

You should consider:

a=-g=-10m/s²

yo=h

If it’s a freefall, it means it starts from rest, which means it has no initial velocity:

Vo=0

Replacing that information in the equation:

y=½*(-10m/s²)*t²+0*t+h=-5m/s²*t²+0+h=-5m/s²*t²+h

So this is the

Besides, if you want to find out how long it takes for it to get to the floor, you should put the height of the floor as final height, which would be 0 (assuming the initial height has been measured from there):

y=0

0=-5m/s²*t²+h

5m/s²*t²=h

t²=h/(5m/s²)

t=√(h/(5m/s²))

t=√(hs²/(5m))

t=(√(h/(5m)))s

If we quadruple h:

t2=(√(h2/(5m)))s=(√(4*h1/(5m)))s=(√4)*(√h1/(5m)))s=2*(√h1/(5m)))s=2*t1

This 4 goes inside the square root, so then it converts to 2. So the new time is twice as much the previous time.

Concerning velocity, you have to use the other equation:

v=at+vo

As I said before, a is gravity and vo is zero.

v=-10m/s²*t+0=-10m/s²*t

Final velocity is directly related to time, so if time is doubled, so is velocity.

v2=-10m/s²*t2=-10m/s²*(2*t1)=2*(-10m/s²*t1)=2*v1

So the correct answer is A, and the other ones are false.

8 0

3 years ago

Which of the following statements is true about a current-carrying wire in a magnetic field? A. Reversing the current direction

Zielflug [23.3K]

B. Reversing the current direction will cause the force deflecting the wire to be perpendicular to the magnetic field but in the opposite direction.

6 0

3 years ago