Answer:
F = 7.2N
Explanation:
The resultant of two forces acting at some angle is given by using the vector addition as given below
F =√F1^2+F2^2+2F1F2cosθ
Where F1 = 6N and F2 = 8N
θ = 240°
Substituting the values into the equation above
F = √ 6^2+8^2+ 2(6×8)cos240
F =√ 36+64+96cos240
F = √ 100+96 ×-0.5
F = √ 100-48
F = √ 52
F = 7.211
F = 7.2N
Answer:
C. 5.6 × 10^11 N/C
Explanation:
The electric field
at a distance
from a charge
is given by

where
is the coulomb's constant.
Now, in our case

;
therefore,


which is choice C from the options given<em> (at least it resembles it).</em>
Angstrom = 10^-10 m
for nucleus size are used fermi (femtometer 10^-15 m )
B student 2 because you add
Draw a diagram to illustrate the problem as shown below.
The vertical component of the launch velocity is
v = (8.5 m/s)*sin30° = 4.25 m/s
The horizontal component of the launch velocity is
8.5*cos30° = 7.361 m/s
Assume that aerodynamic resistance may be ignored.
Because the horizontal distance traveled is 19 m, the time of travel is
t = 19/7.361 = 2.581 s
The downward vertical travel is modeled by
h = (-4.25 m/s)*(2.581 s) + 0.5*(9.8 m/s²)*(2.581 s)²
= 21.675 m
Answer: The height is 21.7 m (nearest tenth)