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Vinil7 [7]
3 years ago
12

It is 5.00 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10.0 k

m/hr (which uses up energy at the rate of 700 W ), or you could walk it leisurely at 3.00 km/hr (which uses energy at 290 W ).A. Which choice would burn up more energy? 1. running.2. walking.B. How much energy (in joules) would it burn?C. Why is it that the more intense exercise actually burns up less energy than the less intense one?
Physics
1 answer:
8_murik_8 [283]3 years ago
4 0

Answer:

a. Walking burns up more energy.

b. 1740 kJ

c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.

Explanation:

a. We know energy W = Pt where P = power and t = time.

Now for walking, t = d/v where d = distance = 5.00 km and v = speed = 3.00 km/hr and P = 290 W

So, t = d/v = 5.00 km/3.00 km/hr = 5/3 hr = 5/3 × 3600 s = 6000 s

W = Pt = 290 W × 6000 s = 1740000 = 1740 kJ

Now for running, t = d/v where d = distance = 5.00 km and v = speed = 10.00 km/hr

So, t = d/v = 5.00 km/10.00 km/hr = 0.5 hr = 0.5 × 3600 s = 1800 s and P = 700 W

W = Pt = 700 W × 1800 s = 1260000 = 1260 kJ

Since walking burns up 1740 kJ and running burns up 1260 kJ, walking burns up more energy.

b. It burns up 1740 kJ

c. This is because more intense exercise releases a lot of energy in a short period of time, whereas, less intense energy releases it energy gradually over a long period of time.

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m (mass) = 1 Kg
s (speed) = 3 m/s
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A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of
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Sum the forces in the y direction:

∑F = ma

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Sum the forces in the x direction:

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μ = (164 N cos 10.0°) / (65.0 kg × 9.8 m/s² − 164 N sin 10.0°)

μ = 0.265

7 0
3 years ago
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