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Oksi-84 [34.3K]
3 years ago
10

A boat is moving at the rate of 15.0 meters per second. It’s speed is then decreased uniformly to 3.0 meters per second. It take

s 4 seconds for the speed to decrease. What is the magnitude of the deceleration of the car ?
Physics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

-3 m/s²

Explanation:

The formula for deceleration is given as the change in speed over a period of time

Given that,

Initial speed = 15 m/s

Final speed = 3 m/s

change in speed= 3-15= -12 m/s

Time taken= 4 sec

Deceleration = -12/4 = -3 m/s²

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need a picture to answer specific questions.

Explanation:

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4 0
3 years ago
Your 64-cm-diameter car tire is rotating at 3.3 rev/swhen suddenly you press down hard on the accelerator. After traveling 250 m
umka21 [38]

Answer:

0.76 rad/s^2

Explanation:

First, we convert the original and final velocity from rev/s to rad/s:

v_o = 3.3\frac{rev}{s} * \frac{2\pi rad}{1rev} =20.73 rad/s

v_f = 6.4\frac{rev}{s} * \frac{2\pi rad}{1rev}=40.21 rad/s

Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:

D = x*r \\x = \frac{D}{r} = \frac{250m}{0.64m/2} = 781.25 rads

Now, we just use the formula:

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\alpha =\frac{w_f^2-w_o^2}{2x} = \frac{(40.21rad/s)^2-(20.73rad/s)^2}{2*781.25rad} = 0.76 rad/s^2

6 0
3 years ago
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What phenomena provides <br> evidence of electric fields in the atmosphere
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ASHA 777 [7]

Answer:

\frac{dQ}{dt} =-hA\Delta T(t)

Explanation:Newton.s law of cooling states that the rate of cooling of an object is proportional to the difference between its own temperatures and temperature of its surroundings. Mathematically,

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\frac{dQ}{dt} =-hA\Delta T(t)

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3 years ago
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