Answer:
okokok
Step-by-step explanation:
Answer:
(0,27)
Step-by-step explanation:
x2 + 27 = 0
Solutions based on quadratic formula:
x1
= −0 − √ 02 − 4×1×27
2×1
= 0 − 6 × √ 3 i
2
≈ −5.196152i
x2
= −0 + √ 02 − 4×1×27
2×1
= 0 + 6 × √ 3 i 2
≈ 5.196152i
Extrema:
Min = (0, 27)
Answer:
91/216
Step-by-step explanation:
The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.
P(at least one 4) = 1 − P(no 4s)
P(at least one 4) = 1 − (5/6)³
P(at least one 4) = 91/216
Alternatively, you can calculate it this way.
The probability of getting a 4 on the first roll is 1/6.
The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.
The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.
The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.
For this case we have the following equation:
If we add 1 to both sides of the equation we have:
Dividing between 2 on both sides of the equation we have:
The graph of the solution is shown in the attached figure.
Answer:
See attached image
