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4 years ago

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What are the chemical properties of metals

1 answer:

Grace [21]4 years ago

8 0

Answer:

The density of metals are usually high
They are great conductors of heat
They are malleable and ductile

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The importance of reading a circuit diagram to interpret a wiring diagram?

Nataly [62]

Answer:

The ability to read electrical schematics is a really useful skill to have. To start developing your schematic reading abilities, it's important to memorize the most common schematic symbols. ... You should also be able to get a rough idea of how the circuit works, just by looking at the schematic.

Explanation:

7 0

3 years ago

Steam enters an adiabatic turbine at 800 psia and9008F and leaves at a pressure of 40 psia. Determine themaximum amount of work

Naily [24]

Answer:

$w_{out}=319.1\frac{BTU}{lbm}$

Explanation:

Hello,

In this case, for the inlet stream, from the steam table, the specific enthalpy and entropy are:

$h_1=1456.0\frac{BTU}{lbm} \ \ \ s_1=1.6413\frac{BTU}{lbm*R}$

Next, for the liquid-vapor mixture at the outlet stream we need to compute its quality by taking into account that since the turbine is adiabatic, the entropy remains the same:

$s_2=s_1$

Thus, the liquid and liquid-vapor entropies are included to compute the quality:

$x_2=\frac{s_2-s_f}{s_{fg}}=\frac{1.6313-0.39213}{1.28448}=0.965$

Next, we compute the outlet enthalpy by considering the liquid and liquid-vapor enthalpies:

$h_2=h_f+x_2h_f_g=236.14+0.965*933.69=1136.9\frac{BTU}{lbm}$

Then, by using the first law of thermodynamics, the maximum specific work is computed via:

$h_1=w_{out}+h_2\\\\w_{out}=h_1-h_2=1456.0\frac{BTU}{lbm}-1136.9\frac{BTU}{lbm}\\\\w_{out}=319.1\frac{BTU}{lbm}$

Best regards.

3 0

3 years ago

Three spheres are subjected to a hydraulic stress. The pressure on spheres 1 and 2 is the same, and they are made of the same ma

r-ruslan [8.4K]

Answer:

"150000 N/m²" is the right approach.

Explanation:

According to the question, the pressure on the two spheres 1 and 2 is same.

Sphere 1 and 2:

Then,

⇒ $P_1=P_2$

⇒ $\frac{\Delta V_1}{V_1}=\frac{\Delta V_2}{V_2}$

and the bulk modulus be,

⇒ $B_1=B_2$

Sphere 3:

⇒ $\frac{\Delta V_3}{V_3} =\frac{\frac{\Delta V_1}{V_1} }{\frac{\Delta V_2}{V_2} } =1$

then,

⇒ $P_3=B\times \frac{\Delta V_3}{V_3}$

⇒ $=B\times 1$

⇒ $=150000\times 1$

⇒ $=150000 \ N/m^2$

5 0

3 years ago

ngumfowethu kuphela ovunyelwe ukuphendula lo mbuzo ngakho-ke ngicela ungawuphenduli uma uwubona. Ngiyabonga :)

Irina-Kira [14]

Answer:

WHAT?

Explanation:

6 0

3 years ago

Read 2 more answers

What type of figure is this

Vlad1618 [11]

The answer is Ur moms figure

8 0

4 years ago