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3 years ago

5

Use the term interphase in a sentence

2 answers:

natima [27]3 years ago

6 0

Interphase is the process in which all cells go through to be prepared for cell division.
Hope this helps.
(Mark this answer as brainliest if it helped you)
Thanks.

Goshia [24]3 years ago

4 0

DNA replication occurs during the S-stage of INTERPHASE. Also another example is, Many cells can completely undergo INTERPHASE without centrioles.

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What do cuticles do for land plants that was not necessary for ancestors that lived in water?

Vera_Pavlovna [14]

Answer:

What do cuticles do for land plants that was not necessary for ancestors that lived in water? Cuticles help prevent water loss. ... The next groups of land plants to evolve were ferns, which could grow bigger and taller because they could transport water and food.

Explanation:

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3 years ago

Enter a balanced equation for the reaction between aqueous lead(II)(II) nitrate and aqueous sodium chloride to form solid lead(I

aev [14]

Answer:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) ↓ + 2NaNO₃ (aq)

Explanation:

The reactants are:

Lead(II) nitrate → Pb(NO₃)₂ (aq)

Sodium chloride → NaCl (aq)

The products are:

Lead(II) chloride → PbCl₂ (s)

Sodium nitrate → NaNO₃ (aq)

Salts form nitrate are soluble. The chloride makes a precipitate with the Pb²⁺. The chemical equation for this reaction is:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) ↓ + 2NaNO₃ (aq)

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4 years ago

Which of these objects converts light to chemical energy? four objects

Papessa [141]

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A 25.00 mL sample of of a sulfurous acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is t

Kryger [21]

Answer:

0.0445 M is the initial concentration of sulfurous acid.

Explanation:

$H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_3$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=25.00mL\\n_2=1\\M_2=0.13 M\\V_2=17.12 mL$

Putting values in above equation, we get:

$2\times M_1\times 25.00 mL=1\times 0.13 M\times 17.12 mL$

$x=\frac{1\times 0.13 M\times 17.12 mL}{2\times 25.00}=0.0445 M$

0.0445 M is the initial concentration of sulfurous acid.

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3 years ago