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Roman55 [17]
4 years ago
14

Enter a balanced equation for the reaction between aqueous lead(II)(II) nitrate and aqueous sodium chloride to form solid lead(I

I)(II) chloride and aqueous sodium nitrate. Express your answer as a chemical equation. Identify all of the phases in your answer. Pb(NO3)2(aq)+2NaI(aq)→PbI2(s)+2NaNO3(aq) You have already submitted this answer. Enter a new answer. No credit lost. Try again.
Chemistry
1 answer:
aev [14]4 years ago
3 0

Answer:

Pb(NO₃)₂ (aq)  + 2NaCl (aq)  → PbCl₂ (s) ↓  + 2NaNO₃ (aq)

Explanation:

The reactants are:

Lead(II) nitrate → Pb(NO₃)₂ (aq)

Sodium chloride → NaCl (aq)

The products are:

Lead(II) chloride → PbCl₂ (s)

Sodium nitrate → NaNO₃ (aq)

Salts form nitrate are soluble. The chloride makes a precipitate with the Pb²⁺. The chemical equation for this reaction is:

Pb(NO₃)₂ (aq)  + 2NaCl (aq)  → PbCl₂ (s) ↓  + 2NaNO₃ (aq)

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3. What noble gas would be part of the electron configuration notation for Mn?
shusha [124]

Answer:

Argon {Ar}

Explanation:

The noble gas used for a condensed electron configuration is the one before the element which you are configuring.

In this case, the element (Mn) is manganese

The noble gas that is before this element is Argon which is the row above it

so your configuration would be {Ar} 3d^5 4s^2

7 0
3 years ago
The substance argon has the following properties: normal melting point: 83.9 K normal boiling point: 87.4 K triple point: 0.68 a
Vsevolod [243]

Answer:

The final state of the substance is a gas.

The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Let's consider the phase diagram for Argon (not to scale).

<em>A sample of argon is initially at a pressure of 49.6 atm and a temperature of 101.4 K. The pressure on the sample is reduced to 0.680 atm at a constant temperature of 101.4 K. Which of the following are true? Choose all that apply </em>

<em>The final state of the substance is a gas.</em> TRUE. At 0.680 atm and 101.4 K, the substance is a gas.

<em>The gas initially present will solidify.</em> FALSE. Initially, Ar is present as a liquid.

<em>The final state of the substance is a solid.</em> FALSE.

<em>The sample is initially a liquid. One or more phase changes will occur.</em> TRUE. The sample is initially liquid and only one phase change will occur.

5 0
4 years ago
An electrochemical cell has the following standard cell notation.
icang [17]

The cell notation is:

Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

E^{0}_{Mg}=-2.38V

E^{0}_{Ag}=+0.80V

Therefore

E^{0}_{cell}=0.80-(-2.38)=+3.18V

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

ΔG^{0}=-nFE^{0}

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

7 0
3 years ago
Why methylene blue is blue
bixtya [17]

Methylene blue indicates the presence of oxidizing agents because it is oxidized itself by these compounds. When electrons are stripped from methylene blue, the resulting molecule imparts a blue color to the solution--giving a clear sign of a chemical change.

7 0
3 years ago
Which of these substances has the lowest pH? 0.5 M HBr, pOH = 13.5 0.05 M HCl, pOH = 12.7 0.005 M KOH, pOH = 2.3
vagabundo [1.1K]
<h3><u>Answer;</u></h3>

0.5 M HBr, pOH = 13.5 ; Has the lowest pH

<h3><u>Explanation;</u></h3>

From the question;

pH = -Log [OH]

or pH = 14 - pOH

Therefore;

For 0.5 M HBr

[H+] = 0.5 M

pH = - Log [0.5]

     = 0.30

For;  pOH = 13.5

pH = 14 - pOH

     = 14 -13.5

     = 0.5

For; 0.05 M HCl

pH = - log [H+]

[H+] = 0.05

pH = - Log [0.05]

     = 1.30

For; pOH = 12.7

pH = 14 -pOH

     = 14 -12.7

     = 1.30

For;  0.005 M KOH,

pOH = - log [OH]

[OH-] = 0.005

pOH = - Log 0.005

        = 2.30

pH = 14 - 2.30

     = 11.7

For; pOH = 2.3

   pH = 14 -pOH

         = 14- 2.3

         = 11.7

6 0
3 years ago
Read 2 more answers
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