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Roman55 [17]
4 years ago
14

Enter a balanced equation for the reaction between aqueous lead(II)(II) nitrate and aqueous sodium chloride to form solid lead(I

I)(II) chloride and aqueous sodium nitrate. Express your answer as a chemical equation. Identify all of the phases in your answer. Pb(NO3)2(aq)+2NaI(aq)→PbI2(s)+2NaNO3(aq) You have already submitted this answer. Enter a new answer. No credit lost. Try again.
Chemistry
1 answer:
aev [14]4 years ago
3 0

Answer:

Pb(NO₃)₂ (aq)  + 2NaCl (aq)  → PbCl₂ (s) ↓  + 2NaNO₃ (aq)

Explanation:

The reactants are:

Lead(II) nitrate → Pb(NO₃)₂ (aq)

Sodium chloride → NaCl (aq)

The products are:

Lead(II) chloride → PbCl₂ (s)

Sodium nitrate → NaNO₃ (aq)

Salts form nitrate are soluble. The chloride makes a precipitate with the Pb²⁺. The chemical equation for this reaction is:

Pb(NO₃)₂ (aq)  + 2NaCl (aq)  → PbCl₂ (s) ↓  + 2NaNO₃ (aq)

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Consider the ideal gas law:

P\cdot V = n\cdot R\cdot T,

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The question is asking for the final volume V of the gas. Rearrange the ideal gas equation for volume:

V = \dfrac{n \cdot R \cdot T}{P}.

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V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}.

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The volume of the gas is proportional to the reciprocal of its absolute temperature \dfrac{1}{T} if both n and T stays constant. In other words,

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(3 sig. fig. as in the question.).

See if you get the same result if you hold T constant, change P, and then move on to change T.

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