Answer: C) (x + 5i)(x - 5i)
<u>Step-by-step explanation:</u>
Factor using the difference of squares: a² - b² = (a + b)(a - b)
x² + 25
= x² - -25
= √(x²) - √-25
a=x b=5i
= (x + 5i)(x - 5i)
The third option I believe
You should use Socratic it’s gives you all the answers quickly and it will explain to you how it’s done. They also don’t give you ads.
Half-life (t½) is the amount of time required for a quantity to fall to half its value as measured at the beginning of the time period.
(t½) of C-14 is 5730 years, which means that after 5730 years half of the sample would have decayed and half would be left as it is.
After 5730 years ( first half life) 70 /2 = 35 mg decays and 35 g remains left.
After another 5730 years ( two half lives or 11460 years) 35 /2 = 17.5mg decays and 17.5 g remains left .
After another 5730 years ( three half lives or 17190 years) 17.5 /2 = 8.75mg decays and 8.75g remains left.
after three half lives or 17190 years, 8.75 g of C-14 will be left.
Answer:
a few examples can be -20 + -25 and 5 + -55
Step-by-step explanation: