Answer:1.89 m
Explanation:
Given
Block travels in first second
It is released from rest i.e. initial speed is zero (u=0)
using
where a=acceleration
here acceleration is the component of gravity on incline plane (say )
so
So distance traveled in
So distance traveled in is
The total energy remains the same, as long as
none of it escapes the closed system.
Answer: 13.46 m/s
Explanation:
Initial velocity V1 = 5.82 m/s
acceleration A = 2.35m/s^2
Time taken T = 3.25s
Final velocity V2 = ?
Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (V2 - V1)/T
2.35m/s^2 = (V2 - 5.82 m/s) / 3.25s
cross multiply
2.35m/s^2 x 3.25s = (V2 - 5.82 m/s)
7.6375m/s = V2 - 5.82 m/s
V2 = 7.6375m/s + 5.82m/s
V2 = 13.46 m/s
Thus, the car final velocity is 13.46 m/s
Answer:
The force of the air on the skydiver's body is:
Explanation:
Let's recall that when an object reached terminal velocity, the force of the air acting is equal to the weight of the object, so the net force will be zero, that is why the object falls at a constant speed.
Then we have:
where:
m is the mass of the skydiver (65 kg)
g is the gravity acceleration (9.81 m/s²)
Therefore, the force of the air on the skydiver's body is:
I hope it helps you!