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3 years ago

True or false/ the thermal energy of an object is the total energy of the particles in a material

Physics

2 answers:

amm18123 years ago

4 0

The right answer is True

Stolb23 [73]3 years ago

4 0

Answer:

True

Explanation:

I took the test

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What kind of lens is there in our eyes? where does it form the image of an object?

Goshia [24]

Answer:

convex lens

Explanation:

An image is form in retina with light rays converging most at cornea and upon entering and existing the lens.Rays from top and bottom of the object are traced and produce an inverted image on the retina

8 0

2 years ago

A 0.49 m copper rod with a mass of 0.15 kg carries a current of 13 A in the positive y direction. Let upward be the positive dir

Helen [10]

Answer:

Magnetic field, B = 0.23 T

Explanation:

Given that,

Length of the copper rod, L = 0.49 m

Mass of the copper rod, m = 0.15 kg

Current in rod, I = 13 A (in +ve y direction)

When the rod is placed in magnetic field, the magnetic force is balanced by its weight such that :

$BIL=mg\\\\B=\dfrac{mg}{IL}\\\\B=\dfrac{0.15\times 9.8}{13\times 0.49}\\\\B=0.23\ T$

So, the magnitude of the minimum magnetic field needed to levitate the rod is 0.23 T.

6 0

3 years ago

A right-circular cylindrical tank of height 8 ft and radius 4 ft is laying horizontally and is full of fuel weighing 52 lb/ft3

tresset_1 [31]

Given:

Height of tank = 8 ft

and we need to pump fuel weighing 52 lb/ $ft^{3}$ to a height of 13 ft above the tank top

Solution:

Total height = 8+13 =21 ft

pumping dist = 21 - y

Area of cross-section = $\pi r^{2}$ = $\pi 4^{2}$ =16 $\pi$ $ft^{2}$

Now,

Work done required = $\int_{0}^{8} 52\times 16\pi (21 - y)dy$

= $832\pi \int_{0}^{8} (21 - y)dy$

= 832 $\pi($ $[ 21y ]_{0}^{8} - [\frac{y^{2}}{2}]_{0}^{8}\\$ )

= 113152 $\pi$ = 355477 ft-lb

Therefore work required to pump the fuel is 355477 ft-lb

7 0

3 years ago

A student wants to approximate the amount of work that the force due to gravity does on the student as the student walks up a se

Inessa [10]

Answer:

Options A and D

Explanation:

In this question the student needs to collect these measurements in order to approximate the work done

A. The mass of the student

D. The final vertical height above the initial vertical position.

Workdone = mgh

m = mass

g = gravity = 9.8m/s²

h = vertical height between the initial and the final positions.

The vertical height has to be known as gravity only acts straight down.

3 0

3 years ago

Some tropical butterflies can reach speeds of up to 11 m/s. Suppose a butterfly flies at a speed of 6.0m/s while another flying

ladessa [460]

Answer:

24.3 m

Explanation:

Using the equation of motion

$S=ut+0.5at^{2}$ where s is the distance, u is initial velocity, t is time and a is acceleration

Substituting u for 6 m/s, t for 3 s, a for 1.4 m/s2 we obtain

$S=6*3+(0.5*1.4*3^{2}=18+6.3=24.3 m
$

7 0

3 years ago