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Softa [21]
2 years ago
12

When is zero considered significant​

Physics
2 answers:
Semenov [28]2 years ago
7 0

Answer:

The trailing zero to the right in the decimal place and the zero present between the non zero digit are significant.

Explanation:

The rules which describes about the significant digits are discussed below as:

  • All the digits which are non zero are significant. Example 178 has three significant digits.
  • The zero which is present in between two non zero digits are consider significant. Example 507 has 3 significant digits.
  • The leading zeroes are not consider significant. Example 0.00676 has 3 significant digits only.
  • Trailing zero to the right in the decimal is consider significant. Example 3.0 has 2 significant digits.
  • Trailing zero which is present in the whole number without any decimal are not significant. Example 9800 has only 2 significant digit.

vazorg [7]2 years ago
3 0

If a zero is found between significant digits, it is significant. Zeros can be used as (insignificant) place holders to the left of significant digits if the number is a decimal. For example, a mass of 42 g has two significant digits. Expressed in kilograms, the mass of 0.042kg should still have two significant digits.

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A substance freezes at -58c therefore substance melts at ?
Yanka [14]
The freezing point is the same as the melting point.

If it freezes at -58°C, hence the melting point is also <span>-58°C.</span>
3 0
2 years ago
002 10.0 points
snow_lady [41]

Answer:

-2040 m/s²

Explanation:

Taking toward the wall to be positive, the initial velocity is 10.1 m/s and the final velocity is -8.3426 m/s.

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (-8.3426 m/s − 10.1 m/s) / 0.00905 s

a = -2040 m/s²

3 0
2 years ago
A type of light bulb is labeled having an average lifetime of 1000 hours. It’s reasonable to model the probability of failure of
SashulF [63]

Answer:

0.2592 \ or \ 25.92\%

Explanation:

The exponential density function is given as

f(t)=\left \{ {{0} \atop {ce^{ct}}} \right\\0,t

\mu=\frac{1}{c}\\c=\frac{1}{\mu}\\\\=\frac{1}{1000}=0.001\\\\f(t)=0.001e^{-0.001t}

To find probability that bulb fails with the first 300hrs, we integrate from o to 300:

P(0\leq X\leq 300)=\int\limits^{300}_0 {f(t)} \, dt\\\\=\int\limits^{300}_0 {0.001e^{-001t}} \, dt\\ =|-e^{-0.001t}|  \ 0\leq t\leq 300

P(0\leq X\leq 300)=-0.7408+1\\=0.2592

Hence probability of bulb failing within 300hrs is 25.92% or 0.2592

3 0
2 years ago
If the mass is 2.0 kg and the acceleration is 5 m/s/s, then what is the force?
pshichka [43]

Answer:

Explanation:

F = ma = 2.0(5) = 10 N

5 0
2 years ago
In the process of photosynthesis, how do plants obtain the water, carbon dioxide, and energy they use for this process?
NNADVOKAT [17]

Answer:

They get it from the air and soil. They also take energy from the sun.

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil.

3 0
2 years ago
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