Complete question:
At a particular instant, an electron is located at point (P) in a region of space with a uniform magnetic field that is directed vertically and has a magnitude of 3.47 mT. The electron's velocity at that instant is purely horizontal with a magnitude of 2×10⁵ m/s then how long will it take for the particle to pass through point (P) again? Give your answer in nanoseconds.
[<em>Assume that this experiment takes place in deep space so that the effect of gravity is negligible.</em>]
Answer:
The time it will take the particle to pass through point (P) again is 1.639 ns.
Explanation:
F = qvB
Also;

solving this two equations together;

where;
m is the mass of electron = 9.11 x 10⁻³¹ kg
q is the charge of electron = 1.602 x 10⁻¹⁹ C
B is the strength of the magnetic field = 3.47 x 10⁻³ T
substitute these values and solve for t

Therefore, the time it will take the particle to pass through point (P) again is 1.639 ns.
Explanation:
London dispersion forces will form between non-polar molecules(polar ) that are symmetrical like O₂, H₂, Cl₂ and noble gases.
- The attraction here is because non-polar molecules becomes polar due to the constant motion of its electrons.
- This lead to an uneven charge distribution at an instant.
- A temporary dipole or instantaneous dipole forms.
- The temporary dipole can induce neighboring molecules to be distorted and forms dipoles as well.
- This forms london dispersion forces.
Learn more:
Intermolecular forces brainly.com/question/10602513
#learnwithBrainly
1. B- electric generator
Although its really sometimes called an AC generator.
- i hoped i helped u :)
Answer: 110000
Explanation:
26/9=30.5555555556
30.5555555556 x 60=1833.33333333
110000 x 60=110000