Answer:
Explanation:
In a quiet forest, you can sometimes hear a single leaf fall to the ground. ... greater its pressure amplitude, the more the air is compressed in the sound it creates. ... Graphs of the gauge pressures in two sound waves of different intensities. ... The sound intensity level β in decibels of a sound having an intensity I in watts per .
I would expect it to be slightly basic.
C.) Laser. the light from the laser reflects off the shiny surface as the CD rotates
Answer
given,
mass of jogger = 67 kg
speed in east direction = 2.3 m/s
mass of jogger 2 = 70 Kg
speed = 1.3 m/s in 61 ° north of east.
jogger one
![P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}](https://tex.z-dn.net/?f=P_2%20%3D%2070%5Ctimes%20v%20cos%20%5Ctheta%20%5Chat%7Bi%7D%20%2B70%5Ctimes%20v%20sin%20%5Ctheta%20%5Chat%7Bj%7D%20)
now
P = P₁ + P₂
magnitude
![P = \sqrt{198.22^2 + 79.59^2}](https://tex.z-dn.net/?f=P%20%3D%20%5Csqrt%7B198.22%5E2%20%2B%2079.59%5E2%7D)
![P =213.60 kg.m/s](https://tex.z-dn.net/?f=P%20%3D213.60%20kg.m%2Fs)
![\theta = tan^{-1}\dfrac{79.59}{198.22}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cdfrac%7B79.59%7D%7B198.22%7D)
![\theta = 21.87](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2021.87)
the angle is
north of east
Answer:
W=315 x 10⁵ J
Explanation:
Given that
F= 2.5 x 10⁵ N
d= 90 m
K.E.=5.4 x 10⁷ J
We know that work done by all force is equal to the change in kinetic energy
Lets take work done by catapult is W
W + F.d= K.E.
W= 5.4 x 10⁷ - 2.5 x 10⁵ x 90 J
W= (540 - 25 x 9) 10⁵ J
W=315 x 10⁵ J