Answer:
So then the difference of temperature across the material would be 
Explanation:
For this case we can use the Fourier Law of heat conduction given by the following equation:
(1)
Where k = thermal conductivity = 0.2 W/ mK
A= 1m^2 represent the cross sectional area
Q= 3KW represent the rate of heat transfer
is the temperature of difference that we want to find
represent the thickness of the material
If we solve 
in absolute value from the equation (1) we got:
First we convert 3KW to W and we got:
And we have everything to replace and we got:
So then the difference of temperature across the material would be
Answer:
The missing species is carbon-12 
.
The nuclear equation should be 
.
Explanation:
Let 
represent the mass number of the missing species, and let 
represent its atomic number.
.
For this question, there are three things to consider:
- The sum of the mass numbers should be conserved.
- Since there's no beta particle (
or 
) involved, the sum of the atomic numbers should also be conserved. - The atomic number of the missing species should correspond to atomic symbol.
<h3>Mass Number</h3>
The sum of the mass numbers on the left-hand side of this reaction is: 
.
The sum of the mass number on the right-hand side (including that of the missing species) is 
.
These two numbers should be the same. In other words, 
. Therefore, the mass number of the missing species would be 
.
<h3>Atomic Number</h3>
The sum of the atomic numbers on the left-hand side of this reaction is: 
.
The sum of the mass number on the right-hand side (including that of the missing species) is 
.
These two numbers should be the same. In other words, 
. Therefore, the mass number of the missing species would be 
.
<h3>Symbol</h3>
The atomic number of the missing species is . Look up a modern periodic table. The element with atomic number
Answer:
Option a. the number of transistors per square inch on integrated circuits will double every two years.
Explanation:
Moore's law states that the number of transistors in an integrated circuit will double every two years.
The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
