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1 year ago

How does a push or pull affect motion?

Physics

1 answer:

STatiana [176]1 year ago

8 0

Answer:

The motion of an object acted on by a force depends partly on the strength of the push or pull. The stronger the push or pull, the faster the object will move.

Explanation:

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Which of the following is the best example of a good hypothesis?

Musya8 [376]

Answer:

Which of the following is the best example of a good hypothesis?

B. A cheetah can run faster than a tiger This Is A good Hypothesis Because You Can Test this With a Experiment

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2 years ago

Read 2 more answers

An unstrained horizontal spring has a length of 0.31 m and a spring constant of 220 N/m. Two small charged objects are attached

Kruka [31]

The solution you should use is Hooke's law: F=-kx

It should have the same signs because they repel due to the stretch of the spring.

a. Since there is a constant energy within the spring, then Hooke's law will determine the possible algebraic signs. The solution should be
<span>F = kx
270 N/m x 0.38 m = 102.6 N
</span>
b. Then use Coulomb's law; F=kq1q2/r^2 to find the charges produced in the force.

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3 years ago

When an object is raised vertically, work is done against __________. What one word completes the sentence?

Rasek [7]

Gravity Gravitational Force of Gravity

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2 years ago

Which of the following best describes the energy transformations that take place when a battery-powered dvd player is used to wa

AveGali [126]

D. chemical to electrical to sound and electromagnetic

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3 years ago

Hey guys.. ans me

Stels [109]

The time taken by the swimmer was 1 hour.

Why?

Since the swimmer is maintaining an angle of 150° while he was swimming, there were two components of the speed (horizontal and vertical). If we want to calculate the time taken by him to cross the river, we need to calculate the vertical speed and consider that the flow's speed is compensated by his horizontal speed.

We can calculate both components of the speed using the following formula:

$HorizontalSpeed=Speed*Cos(150\°)\\\\VerticalSpeed=Speed*Sin(150\°)$

Now, calculating we have:

$HorizontalSpeed=2\frac{Km}{h} *Cos(150\°)=-\sqrt{3} \frac{Km}{h} \\\\VerticalSpeed=2\frac{Km}{h} *Sin(150\°)=1\frac{Km}{h}$

Therefore, we have that the horizontal speed is compesating the flow's speed while his vertical speed is used to cross the river which is 1 Km wide.

Hence, we have that the tame taken is:

$Time=\frac{RiverWidth}{VerticalSpeed}=\frac{1Km}{1\frac{Km}{h} } =1h$

Have a nice day!

7 0

2 years ago