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yanalaym [24]
3 years ago
9

The following three resistors (Ohms) are in parallel with one voltage source. What is the total current running through circuit?

Physics
1 answer:
Zepler [3.9K]3 years ago
6 0

Explanation:

The total resistance Rt is given by

1/Rt = 1/Ra + 1/Rb + 1/Rc = 1/5 + 1/4 + 1/7 = 0.593

or Rt = 1.69 ohms

The total current I running through the circuit is

I = V/Rt = 2.37 A

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. Boa constrictor snakes have tiny pelvic girdles and leg bones within their bodies. Since these structures are not functional,
blondinia [14]

Those organic structures that do not seem to play any important biological function in the organism that possesses them are known as vestigial structures.

<h2>What is a vestigial structure?</h2>

A vestigial structure is one that has atrophied or lost its original function throughout the course of evolution.

  • It generally refers to those organic structures that were useful at some point, but are now practically or totally useless.

  • These structures are preserved as an inheritance of the evolutionary process, because at some point an ancestor of the current species had that structure, which was functional, but it ceased to be important and would end up atrophy.

Therefore, we can conclude that vestigial structures are structures that some organisms still conserve as an inheritance from their ancestors but that, for some reason or another, are no longer useful for the functioning of the same.

Learn more about vestigial structures here: brainly.com/question/2141655

4 0
2 years ago
One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe
Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

\mu = \frac{m}{l}

\mu = \frac{8.79*10^{-3}}{70*10^{-2}}

\mu = 0.01255kg/m

The expression for the wavelength of the standing wave for the second overtone is

\lambda = \frac{2}{3} l

Replacing we have

\lambda = \frac{2}{3} (70*10^{-2})

\lambda = 0.466m

The frequency of the sound wave is

f_s = \frac{v}{\lambda_s}

f_s = \frac{344}{0.768}

f_s = 448Hz

Now the velocity of the wave would be

v = f_s \lambda

v = (448)(0.466)

v = 208.768m/s

The expression that relates the velocity of the wave, tension on the string and linear mass density is

v = \sqrt{\frac{T}{\mu}}

v^2 = \frac{T}{\mu}

T= \mu v^2

T = (0.01255kg/m)(208.768m/s)^2

T = 547N

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the n^{th} harmonic frequency is

f_n = nf_1

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

n=3

Then,

f_3 = 3f_1

Rearranging to find the fundamental frequency

f_1 = \frac{f_3}{3}

f_1 = \frac{448Hz}{3}

f_1 = 149.9Hz

7 0
3 years ago
Discuss the differences between Seismic Reflection and Seismic Refraction
Maru [420]

Explanation:

Seismic refraction is the bending of the seismic waves as they pass geological layers of the earth due to different densities. This is especially true for Primary waves because they can pass through all the layers of the earth both liquid and solid.

Seismic reflectivity is the bouncing back of seismic waves at a boundary of geological layers due to different densities or subsurface formation. This is especially true for secondary waves that are unable to pass through liquid layers of the earth like the outer core and mantle. When they reach the boundary of these layers they bounce back towards the earth's surface.

These properties of P and S waves are used to ‘auscultate’ the epicenter of an earthquake by triangulation.

Learn More:

For more on Seismic Reflection and Seismic Refraction check out;

brainly.com/question/13502364

#LearnWithBrainly

6 0
3 years ago
What is the mass of 3.70 L of water? Remember 1000 L = 1 m^3 (Unit=Kg)
xxMikexx [17]

Answer:

3.7kg

Explanation:

The following data were obtained from the question:

Volume = 3.7L

Mass =?

Next, we shall convert 3.7L to m³.

This is illustrated below:

1000L = 1m³

Therefore, 3.7L = 3.7/1000 = 0.0037m³

Now, we can obtain the mass of the water as shown below:

Density of water = 1000kg/m³

Volume of water = 0.0037m³

Mass of water =..?

Density = Mass /volume

1000kg/m³ = Mass /0.0037m³

Cross multiply

Mass = 1000Kg/m³ × 0.0037m³

Mass = 3.7Kg

Therefore, the mass of the water is 3.7Kg.

8 0
3 years ago
Snow tends to sublime outside during cold, clear winter days when the atmospheric pressure is low. During this proces
olga nikolaevna [1]
A I think because sublimation is when something skips melting and goes directly to vapor
3 0
3 years ago
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