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3 years ago

The following three resistors (Ohms) are in parallel with one voltage source. What is the total current running through circuit?

Physics

1 answer:

Zepler [3.9K]3 years ago

6 0

Explanation:

The total resistance Rt is given by

1/Rt = 1/Ra + 1/Rb + 1/Rc = 1/5 + 1/4 + 1/7 = 0.593

or Rt = 1.69 ohms

The total current I running through the circuit is

I = V/Rt = 2.37 A

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2 years ago

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andrew11 [14]

Answer:

2.8 cm

Explanation:

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$\beta_1=\dfrac{y_1}{2}\\\Rightarrow \beta_1=\dfrac{1.4}{2}\\\Rightarrow \beta_1=0.7\ cm$

Fringe width is also given by

$\beta_1=\dfrac{m_1\lambda D}{d}\\\Rightarrow d=\dfrac{m_1\lambda D}{\beta_1}$

For second order

$\beta_2=\dfrac{m_2\lambda D}{d}\\\Rightarrow \beta_2=\dfrac{m_2\lambda D}{\dfrac{m_1\lambda D}{\beta_1}}\\\Rightarrow \beta_2=\dfrac{m_2}{m_1}\beta_1$

Distance between two second order minima is given by

$y_2=2\beta_2$

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3 years ago

Nuclei of u-238 atoms are

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3 years ago

A spring stretches 3.5 cm when a 9 g object is hung from it. The object is replaced with a block of mass 26 g which oscillates i

evablogger [386]

Answer:

The period of motion of new mass T = 0.637 sec

Explanation:

Given data

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$k = \frac{F}{x}$

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Now the period of motion is given by

$T = 2 \pi \sqrt{\frac{m}{k} }$

$T = 2 \pi \sqrt{\frac{0.026}{2.522} }$

T = 0.637 sec

This is the period of motion of new mass.

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2 years ago

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3 years ago