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Rufina [12.5K]
3 years ago
15

(Surds) Write √99 + √44 in the form a√b where a and b are integers

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Because we know that 9 (11) = 99 and 4(11) = 44 then we can deduce that the simplified integer form must be \sqrt{9} (\sqrt{11} ) & \sqrt{4} (\sqrt{11}). So the correct answer becomes 3\sqrt{11}  +2\sqrt{11}, this means the final answer is 5\sqrt{11}.

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Help pleaseeeeeee!!!!!!!
tigry1 [53]

Answer:

a) 100π

Step-by-step explanation:

A = πr²

A = (10²)π

A = 100π

7 0
3 years ago
Can some one help me with geometry
Anuta_ua [19.1K]
Um, what about geometry? What problem?
7 0
3 years ago
Please help out guys.
Kobotan [32]

Answer:

39

Step-by-step explanation:

-\left(\left(-1\right)^2-4\right)^3-4\left(-3\right)

=-\left(-3\right)^3-4\left(-3\right)

=-\left(-27\right)-4\left(-3\right)

=-\left(-27\right)-\left(-12\right)

=39

7 0
3 years ago
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?
Pavel [41]

\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Explanation:</h2>

Using the quadratic formula:

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}

<h2>Learn more:</h2>

Quadratic functions: brainly.com/question/12164750

#LearnWithBrainly

8 0
3 years ago
What is 7/24 times 8/35?
Serga [27]

Answer:

1/15

Step-by-step explanation:

7/24 * 8/35

1/3*1/5=1/15

4 0
3 years ago
Read 2 more answers
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