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Rufina [12.5K]
3 years ago
15

(Surds) Write √99 + √44 in the form a√b where a and b are integers

Mathematics
1 answer:
docker41 [41]3 years ago
8 0

Because we know that 9 (11) = 99 and 4(11) = 44 then we can deduce that the simplified integer form must be \sqrt{9} (\sqrt{11} ) & \sqrt{4} (\sqrt{11}). So the correct answer becomes 3\sqrt{11}  +2\sqrt{11}, this means the final answer is 5\sqrt{11}.

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Simplify 4√16 + 8√16
Mumz [18]

4\sqrt{16} + 8\sqrt{16}:

Since \sqrt{1} =1, we get:

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7\sqrt{4} *3\sqrt{8}

We have \sqrt{4}=2

simplify \sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}

then the radical rule is used: \quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

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Now we have \sqrt{4}=2 and \sqrt{8}=2 \sqrt{2}

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2\sqrt{4}+5 \sqrt{9}

2\sqrt{4} =2*2= 4 and 5\sqrt{9} =5*3= 15

2\sqrt{4}+5 \sqrt{9} = 4+15 = 19

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4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}

since 2\sqrt{5} is the half of 4\sqrt{5}

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-4\sqrt{2}\:+\:5\sqrt{2} =1 \sqrt{2} = \sqrt{2}\\    <em>(-4+5=1)</em>

4 0
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