We need to do some general algebra here.
We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.
<em>We know that:</em>
- Each lab group needs 25 ml of solution.
- it takes 15 g of CuNO₃ to make one L of that solution.
- There are 22 labs.
Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the <u>total amount of solution needed</u> is:
22*25ml = 550 ml
Now we know that we need 15 grams to make one liter of solution, and:
1 L = 1000ml
Then you need 15g to make 1000ml
and x (we want to find this amount) to make 550ml
Then we can write two equations (not actual equations, as these are different units) like:
x = 550ml
15g = 1000ml
Now we can take the quotient between these two equations:
x/15 g = (550ml/1000ml)
And now we can solve this for x:
x = (550ml/1000ml)*15g = 8.25g
So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.
If you want to learn more, you can read:
brainly.com/question/8743486
