Answer:
A. Adding another bulb will make the two of them light a little less brighter since the electrical flow is divided into two making them work.
B. There is a possibility that the flow of electricity maybe little due to the thickness of the wire. There could also be a rise in the temperature of the cell and the bulb.
C. The Bulb will shine brighter because of the extra power or electricity provided! Also, if the voltage is too much, expect the bulb to burn out or sadly, explode.
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<span>Answer is: 2940 mL of
the HCL solution.</span>
c₁(HCl) = 10.0 M.
V₂(AgNO₃<span>) = ?.
c</span>₂(AgNO₃<span>) = 0.85 M.
V</span>₁(AgNO₃<span>) = 250 mL </span>÷ 1000 mL/L = 0.25 L.
<span>
c</span>₁<span> - original concentration of the solution, before it
gets diluted.
c</span>₂<span> - final concentration of the solution, after dilution.
V</span>₁<span> - volume to be diluted.
V</span>₂<span> - final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂<span>.
V</span>₂(HCl) = c₁ · V₁ ÷ c₂.
<span>
V</span>₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.
<span>
V</span>₂(HCl) = 2.94 L ·
1000 mL = 2940 mL.
Answer:
(a). 132 × 10^-9 s = 132 nanoseconds.
(b)..176.5 pico-seconds.
Explanation:
(a). At one torr, the first thing to do is to find the speed and that can be done by using the formula below;
Speed = [ (8 × R × T)/ Mm × π]^1/2.
Where Mm = molar mass, T = temperature and R = gas constant.
Speed= [ ( 8 × 8.314 × 300)/ 131.293 × π × 10^-3)^1/2. = 220m/s.
The next thing to do now is to calculate for the degree of collision which can be calculated by using the formula below;
Degree of collision = √2 × π × speed × d^2 × pressure/ K × T.
Note that pressure = 1 torr = 133.32 N/m^2 and d = collision diameter.
Degree of collision = √2 × π × 220 × (4.9 × 10^-10)^2 × 133.32/ 1.38 × 10^-23 × 300.
Degree of collision = 7.55 × 10^6 s^-1.
Thus, 1/ 7.55 × 10^6. = 132 × 10^-9 s = 132 nanoseconds.
(b). At one bar;
1/10^5 × 10^3 × 56.65 = 1.765 × 10^-10 = 176.5 pico-seconds.
The answer is
H. Convert radiant energy into chemical energy through photosynthesis
