Answer:
x = 1.04866
Explanation:
Force can be defined from power energy by the expressions
F =
in this case we are the expression of the potential energy
U =
let's find the derivative
dU / dx = 2.6 ( ) - 4.3 ()
dU / dx =
we substitute
F = + \frac{20.8}{ x^{9} } - \frac{17.2 }{ x^{5} }
at the equilibrium point the force is zero, so
20.8 / 17.2 = x⁴
x⁴ = 1.2093
x =
x = 1.04866
The tension cable is in relation to the amount of pressure placed on the upper plate
Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
Answer:
Mercury is the smallest planet, but its surface gravity is about the same as that of the larger Mars, because Mercury is denser. As such, Saturn is much larger than Earth, but not very dense, so the gravity on Saturn is roughly the same as on Earth. Mars: 0.38 G. Jupiter: 2.53 grams.
Answer:
The velocity of the ball before it hits the ground = 21.4m/s
Explanation:
The question can be solved as a projectile problem. One of the main characteristics of the parabolic motion is the symmetry it has as long as the initial height is equal to the final height with respect to a reference system, the vertical displacement of the horizontal displacement being independent.
The vertical component of velocity is 13m/s
The horizontal component is 17m/s
The ball's pathway is defined by a right angle triangle .
Using Pythagorean
Let vertical component be a
Let horizontal component be b
Let the speed of the ball before hitting the ground be c
Pythagorean is given by:
a^2 + b^2 = c^2
13^2 + 17^2 = c^2
169 + 289 = c^2
458 = c^2
Sqrt(458) = c
21.4 m/s = c