Answer:
I think its object 1
Explanation:
Because the object that has more weight has a greater momentum and the lightest object that has a less momentum will be easier to change because its lighter.
Answer:
2m/s/s
Explanation:
The formula goes- F=MA
F-Force M-Mass & A-Acceleration
We need to rearrange this formula to find the acceleration-
A=F/M
All we need to do now is substitute the values in
A=2000N/1000kg
A=2m/s^2
In the given option the last option (2m/s/s) would be the ans, as it's the same as 2m/s^2
So ya, I guess that's all
Explanation:
The average speed of a modern cruise ship is roughly 20 knots (23 miles per hour), with maximum speeds reaching about 30 knots (34.5 miles per hour).
Answer:
a. wavelength of the sound, 
b. observed frequecy, 
Given:
speed of sound source,
= 80 m/s
speed of sound in air or vacuum,
= 343 m/s
speed of sound observed,
= 0 m/s
Solution:
From the relation:
v =
(1)
where
v = velocity of sound
= observed frequency of sound
= wavelength
(a) The wavelength of the sound between source and the listener is given by:
(2)
(b) The observed frequency is given by:


(3)
Using eqn (2) and (3):

