Answer: 0.6m
Explanation:
Given that:
force = 4.5 N
Work done = 2.7J
Distance moved by the book = ?
Since work is done when force is applied on an object over a distance, apply the formula:
work = force x distance
2.7J = 4.5N x distance
Distance = (2.7J / 4.5N)
Distance = 0.6 m
Thus, the book was moved 0.6 metres far
Well, half-life is the radioactivity of an identified isotope that decreases by half of the actual value.
So, your answer would be C.
<span>The flower width data were collected at about the same time
every day. </span>
According to the research, the responder made with the same
query as this question it is:
<span><span>
1.
</span>The flower width data were collected at about
the same time every day. </span>
Why this choice because, the study is delving into the
effects of morning temperatures on flower width hence, if the scientists
collect flower at the same time –hour or minutes everyday during the period of
the study the variable of time is not allotted from sunrise period to high noon
since it defines time as morning, the variant of time is only inapt.
Answer:
A rise in temperature increases the kinetic energy and speed of particles; it does not weaken the forces between them. The particles in solids vibrate about fixed positions; even at very low temperatures. Individual particles in liquids and gases have no fixed positions and move chaotically.
Explanation:
1) In an uniformly accelerated motion, the acceleration is given by:

where

is the final speed,

is the initial speed, and

is the time interval between the initial and final point of the motion.
Using the data of the problem:

,

, and the time

, the acceleration is

where the negative sign means that the hockey puck is decelerating.
2) The frictional force F between the puck and ice is responsible for the deceleration of the puck, and for second Newton's law this force is equal to the product between the mass of the puck m and the acceleration:

(1)
The frictional force can also be written as

(2)
where

is the coefficient of kinetic friction, and where the negative sign is due to the fact that the frictional force acts against the direction of motion of the puck. By equilizing (1) and (2) we can find the value of this coefficient:
