Answer:
t = 2 s
Explanation:
In order to find the time taken by the stone to fall from the top of the building to the ground we can use 2nd equation of motion. 2nd equation of motion is as follows:
s = Vit + (0.5)gt²
where,
t = time = ?
Vi = Initial Velocity = 20 m/s
s = height of building = 60 m
g = 9.8 m/s²
Therefore,
60 m = (20 m/s)t + (0.5)(9.8 m/s²)t²
4.9t² + 20t - 60 = 0
solving this quadratic equation we get:
t = -6.1 s (OR) t = 2 s
Since, the time cannot be negative in magnitude.
Therefore,
<u>t = 2 s</u>
True: when there is an angle between force and displacement, 
Explanation:
The work done by a force when pushing/pulling an object is given by the equation

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
We have two extreme cases:
- When the force is parallel to the displacement, then
and
, so the work done is maximum and simply becomes

- When the force is perpendicular to the displacement, then
and
, so the work done is zero.
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly
The wavelength of the first order bright band light light is 714 nm .
Explanation:
We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.
The formula is
nλ =d sinθ
where, n is the order of maximum
λ is the wavelength of light
d is the distance between the lines on diffraction grating.
θ is the angle.
For the given equation n is 1 because the problem states that the light forms 1st order bright band
λ is unknown.
d =
or 0.0000014 m
sin (30) = 0.5
so,
1(λ) = (0.0000014)(0.5)
= 0.0000000714
= 714 nm
Thus, The wavelength of the first order bright band light light is 714 nm .
Answer:
The distance is 3.1 m
Explanation:
The position vector of the fly relative to the corner of the wall is
r = (3.1, 0.5).
The distance of the fly from the corner will be calculated as the magnitude of the vector "r"
magnitude of vector 
Since the numbers to be added have only one decimal place 3.<u>1</u> and 0.<u>5</u>, the result of the sum will have to have one decimal place. The result of the square root will also have one decimal place.