When you do work on a object some of your energy is ________ to that object?
1 answer:
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Complete Question
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is
The value for static friction is
Explanation:
From the question we are told that
The mass of the clock is
The first horizontal force is
The second horizontal force is
Generally the static frictional force is equal to the first horizontal force
So
=>
=>
Generally the kinetic frictional force is equal to the second horizontal force
So
The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²
The direction of the acceleration of the ball is downwards
The given parameters
initial velocity of the ball, u = 0
height above the ground, h = 2.2 m
time of motion of the ball, t = 96 ms = 0.096 s
The magnitude of the acceleration of the ball while coming to rest is calculated as;
let the downwards direction of the acceleration be positive
The direction of the acceleration of the ball is downwards
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