1. Find the spring constant k:
F = mg = kx
68 * g = k * 0.0055m
k = 121287.273
2.Find the frequency f:
ω = 2πf = √k/m
f = √(k / m)/ 2π = 1.7
Answer:
Explanation:
Given that, .
Pressure around scuba is
P = 10^5 Pa
1 Pa = 1 N/m²
Then
P = 10^5 N/m²
Descending height
h = 10m
Change in force per unit square centimetre
We know that,
Pressure = Force / Area
Then,
Force / Area is the required question we are finding
Then,
Force / Area = 10^5 N / m²
So, let convert the m² to cm²
100cm = 1m
(100cm)² = (1m)²
10⁴cm² = 1m²
Then,
Force / Area = 10^5 N/m² × 1m² / 10⁴cm²
Force / Area = 10 N/cm²
So, the force per unit square centimeters is 10.
A. Lowering the humidity of the air.
Hope this helps!
<u>Answer
</u>
4.8 A
<u>Explanation
</u>
From the ohm's law,
V = IR
where V is voltage, I is current and R is resistance.
I = V/R
= 12.0/2.5
= 4.8 A
Answer:
Velocity 
V = Q + 3Rt²
at t = 0, 
= Q + 3r(0) ==> Q
at t = T, 
= Q + 3rT²
Work done (W) = ΔKE = 
W = ![\frac{1}{2} m[(Q + 3RT^{2})^{2} - Q^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20m%5B%28Q%20%2B%203RT%5E%7B2%7D%29%5E%7B2%7D%20-%20Q%5E%7B2%7D%5D)
W = 
[Q² + 9R²T⁴ + 2Q(3RT²) - Q²]
W = (9R²T⁴ + 6QRT²)
Explanation:
Differentiate the position.
Find the equation for speed.
Find the initial and final speed.
Use work energy theorem to find the work done by finding the change in kinetic energy.
