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ch4aika [34]
3 years ago
9

Hey, i need help. the teacher provided notes but they don’t explain ANYTHING.

Chemistry
1 answer:
Arlecino [84]3 years ago
5 0

Answer:

I think

1. A

2. 400

3. 100

4. IDK srry

Explanation:

Ijust want to help, but I also want brainliest

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Methanol, CH3OH, is the simplest of the alcohols. It is synthesized by the reaction of hydrogen and carbon monoxide. Write chemi
Serhud [2]

Answer:

The limiting reactant is H₂

Explanation:

The reaction of hydrogen (H₂) and carbon monoxide (CO) to produce methanol (CH₃OH) is the following:

2H₂(g) + CO(g) → CH₃OH(g)

From the balanced chemical equation, we can see that 1 mol of CO reacts wIth 2 moles of H₂. So, the stoichiometric ratio is:

2 mol H₂/1 mol CO = 2.0

We have 500 mol of CO and 750 mol of H₂, so we calculate the ratio to establish a comparison:

750 mol H₂/500 mol CO = 1.5

Since 2.0 > 1.5, we have fewer moles of H₂ than are needed to completely react with 500 moles of CO. In fact, we need 1000 moles of H₂ and we have 750 moles. So, the limiting reactant is H₂.

8 0
3 years ago
Which of these are formed when
makvit [3.9K]
Option d lo siento si es incorrecto
7 0
2 years ago
Which statement is true about crystal lattice energy
Arturiano [62]
Hey there!:

1) The additional stability that accompanies the formation of the network<span>Crystalline is measured as network enthalpy. 
</span>2) The reticular energy is the energy released when the solid Crystal isform from separate ions in the gaseous state. Always exothermic.<span>
3) </span>The enthalpy of the network depends directly on the size of the loads and conversely in the distance between the ions .


hope this helps!
3 0
3 years ago
Read 2 more answers
A compound made of two elements, iridium (Ir) and oxygen (O), was produced in a lab by heating iridium while exposed to air. The
natima [27]
1) Compund Ir (x) O(y)

2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g

3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g

4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g

5) Convert grams to moles

moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles

moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131

6) Find the proportion of moles

Divide by the least of the number of moles, i.e. 0.00656

Ir: 0.00656 / 0.00656 = 1

O: 0.0131 / 0.00656 = 2

=> Empirical formula = Ir O2 (where 2 is the superscript for O)

Answer: Ir O2
5 0
3 years ago
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When the equation N=O/P is solved for P correctly, the equation should read:
zheka24 [161]

Given the equation N=O/P, solve for P by multiplying the left and right by P/N:

N * P/N = O/P * P/N

P = O/N


3 0
3 years ago
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