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vova2212 [387]
2 years ago
14

Name the following aromatic hydrocarbon:

Chemistry
1 answer:
Tresset [83]2 years ago
8 0

3-Methylpentane is the IUPAC name for the substance.

whether in a continuous chain or a ring, the longest chain of carbons joined by a single bond serves as the basis for IUPAC nomenclature. According to a precise set of priorities, all deviations—whether they involve numerous bonds or atoms other than carbon and hydrogen—are denoted by prefixes or suffixes.

+3-Methylpentane is the IUPAC name for the substance in question. It has a lengthy chain of 5 carbon atoms, which gives it the prefix pent-, and a single bond is what gives it the postfix -ane (alkane). Given that the methyl group is present at the third carbon, it is 3-methylpentane.

Learn more about IUPAC Nomenclature here-

brainly.com/question/14379357

#SPJ9

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The reaction 2a + b --> c + d has an activation energy of 80.0 kj/mol. at 320°c, the rate constant k = 1.80 x 10-2 l mol-1 s-
Naddik [55]
To determine the k for the second condition, we use the Arrhenius equation which relates the rates of reaction at different temperatures. We do as follows:

ln k1/k2 = E / R (1/T2 - 1/T1) where E is the activation energy and R universal gas constant.

ln 1.80x10^-2 / k2 = 80000 / 8.314 ( 1/723.15 - 1/593.15)

k2 = 0.3325 L / mol-s
5 0
4 years ago
A ______ in medicine is a form of scientific argumentation in which evidence is used to rule out claims and support the best con
Gekata [30.6K]

Answer: Scientific reasoning

Explanation:

A scientific reasoning can be defined as the justification which connects the evidence with that of the claim and it rules out all those claims that are not supported by any evidence. It explains the fact that how evidence can support a claim and scientifically acceptable conclusion can be drawn. An argument is always based on one or more claims which can either be true or evidentially proved.

5 0
3 years ago
Pls help me this is my last question
asambeis [7]

Answer: how much mass is in a certain amount of space

Explanation: density is g/mL; therefore it’s the mass (g) in a certain amount of space (mL)

7 0
3 years ago
Read 2 more answers
(05.02 LC)<br><br> How many moles of each element are in one mole of Sr(HCO3)2? (3 points)
Nina [5.8K]

Answer:

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles

Explanation:

The given chemical formula of the compound is Sr(HCO₃)₂

The number of atoms of Sr in the compound = 1

The number of atoms of H in the compound = 2

The number of atoms of C in the compound = 2

The number of atoms of O in the compound = 6

The number of atoms of each element present in each formula unit of Sr(HCO₃)₂ is proportional to the number of moles of each atom in one mole of Sr(HCO₃)₂

Therefore;

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles.

5 0
3 years ago
A 10g vial must have 45ml of diluent added to it. it has a powder volume of 5ml. how many mgr will be in each ml of the final so
Semenov [28]

The solution has a concentration 20 mgr in each mL of the final solution.

To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as

M = m/V

where M is concentration, m is mass of solute, V is the total volume of solution.

From the text we know that :

m = 10g

vsolvent = 45mL

vsolute = 5 mL

find the total volume (V)

V = vsolvent + vsolute

V = 45 + 5

V = 50mL

Then, find the concentration

M = m/V

M = 10gr / 50 mL

M = 1000 mgr / 50mL

M = 20 mgr / mL

Hence, the solution has a concentration 20 mgr in each mL of the final solution.

Find more on concentration at: brainly.com/question/17206790

#SPJ4

6 0
2 years ago
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