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1 year ago

Name the following aromatic hydrocarbon:

Chemistry

1 answer:

Tresset [83]1 year ago

8 0

3-Methylpentane is the IUPAC name for the substance.

whether in a continuous chain or a ring, the longest chain of carbons joined by a single bond serves as the basis for IUPAC nomenclature. According to a precise set of priorities, all deviations—whether they involve numerous bonds or atoms other than carbon and hydrogen—are denoted by prefixes or suffixes.

+3-Methylpentane is the IUPAC name for the substance in question. It has a lengthy chain of 5 carbon atoms, which gives it the prefix pent-, and a single bond is what gives it the postfix -ane (alkane). Given that the methyl group is present at the third carbon, it is 3-methylpentane.

Learn more about IUPAC Nomenclature here-

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If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th

qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

$K_c=4.74\times 10^4$

Concentration at equilibrium:

$[COBr_2]=1.58\times 10^{-6}M$

$[Co]=2.78\times 10^{-3}M$

$[Br_2]=2.51\times 10^{-5}M$

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

$COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)$

The expression for reaction quotient will be :

$Q=\frac{[CO][Br_2]}{[COBr_2]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}$

The given equilibrium constant value is, $K_c=4.74\times 10^4$

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When $Q>K_c$ that means product > reactant. So, the reaction is reactant favored.

When $Q$ that means reactant > product. So, the reaction is product favored.

When $Q=K_c$ that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the $Q$ that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

3 0

2 years ago

When road contractors are laying cement,they first place a series of steel rods in a specific patterns. the they pour the cement

Anna11 [10]

The steel rods will enable the concrete to form without any bumps and it will add shape to the cement and strength, so no odd massive lumps are formed.

That is what I think anyways :)

3 0

2 years ago

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Na2SO3" represents sodium sulfite. What does the 4 mean in the formula 4Na2SO3? There are four atoms of sodium. There are four a

MArishka [77]

There are 4 atoms of sodium in the formula of sodium sulfite.

<h3 /><h3>Number of atoms at sodium</h3>

There are 4 atoms of sodium in the formula of sodium sulfite because 4 digit is placed before sodium which shows the number of sodium atom present in the molecule while on the other hand, 2 is placed in front of sulfur which tells us that 2 atoms of sulfur is used in the making of sodium sulfite.

<h3>Reasons of war</h3>

In this excerpt, Paine is attempting to convince the readers that we have righteous reasons to justify supporting the war. We should participate and take part in the war in order to defend ourselves and our country but avoid offensive war to gain financial benefits.

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6 0

2 years ago

There is no sodium found in nature in pure form due to its reactivity. What does this say about activation energy of the reactio

Yuki888 [10]

Answer:

The activation energy of a chemical reaction is the energy that is required to be supplied for a chemical reaction to take place. The activation energy for the reaction of sodium is low compared to the energy released such that the reaction of sodium and water is spontaneous resulting in the melting of the sodium into liquid form

The activation energy of a candle wax is much higher, requiring the ignition of the wick which burns and in turn melts the candle wax to release vapors that burns alongside the wick to produce sooth carbon dioxide, carbon monoxide and water vapor and release of heat energy which also fuels further combustion of the candle wax and wick

Therefore, the activation energy of the candle wax and wick which require the heat of direct flame from an ignited matches is higher than the activation energy of sodium placed in a medium of water that reacts spontaneously without heat application

Explanation:

7 0

3 years ago

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.

Papessa [141]

<u>Answer:</u> The value of equilibrium constant for the net reaction is 11.37

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u> $A+2B\xrightarrow[]{K_1} 2C$

<u>Equation 2:</u> $2C\xrightarrow[]{K_2} D$

The net equation follows:

$D\xrightarrow[]{K} A+2B$

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K=K_1\times \frac{1}{K_2}$

We are given:

$K_1=2.57$

$K_2=0.226$

Putting values in above equation, we get:

$K=2.57\times \frac{1}{0.226}=11.37$

Hence, the value of equilibrium constant for the net reaction is 11.37

6 0

2 years ago