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4 years ago

What is the Titration Method???

Chemistry

1 answer:

SVETLANKA909090 [29]4 years ago

4 0

Answer:

A titration is a technique where a solution of known concentration is used to determine the concentration of an unknown solution. Typically, the titrant (the know solution) is added from a buret to a known quantity of the analyte (the unknown solution) until the reaction is complete.

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Here's the question ~

Lelechka [254]

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

RH = Rydberg constant

nf = final state

ni = initial state

When final state = 3 and initial state = ∞

Then;

1/λ = 1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

1/λ = 1 × 10^7 m-1 (1/3^2 )

λ = 900 nm

Hence, the correct answer is Paschen, ∞ → 3

Learn more about the Rydberg formula; brainly.com/question/17753747

3 0

3 years ago

Read 2 more answers

Which line (A or B) represents a faster speed?

BartSMP [9]

Answer:

Explanation:

Because in 1 second, line A was faster than line B.

3 0

3 years ago

I need half reactions, for the following equation.

zhuklara [117]

Answer : Half reaction is defined as the reaction which will be either the oxidation or reduction reaction of particular species in a given redox reaction.

So as per the definition in the reaction of,

 $Ba + ZnSO_{4} ----\ \textgreater \ BaSO_{4} + Zn$

 $Ba_{(s)} + Zn ^{+2} + SO_{4}^{-2} = Ba^{+2} + SO_{4}^{-2} + Zn_{(s)}$

here on left and right side $SO_{4}^{-2}$ will get cancelled.

and we will get, $Ba_{(s)} + Zn ^{+2} = Ba^{+2} + Zn_{(s)}$

Here,
$Ba_{(s)} ----\ \textgreater \ Ba^{+2} - 2e^{-}$ ...this is oxidation reaction as Ba is getting reduced to $Ba^{+2}$ by losing 2 electrons.

whereas,on the other hand, $Zn ^{+2} ----\ \textgreater \ Zn_{(s)} + 2e ^{-}$ ...this is reduction reaction as $Zn ^{+2}$ is getting reduced to Zn by gaining 2 electrons.

8 0

3 years ago

Calculate the feed ratio of adipic acid and hexamethylene diamine that should be employed to obtain a polyamide of approximately

artcher [175]

Answer:

r= 0.9949 (For 15,000)

r=0.995 (For 19,000)

Explanation:

We know that

Molecular weight of hexamethylene diamine = 116.21 g/mol

Molecular weight of adipic acid = 146.14 g/mol

Molecular weight of water = 18.016 g/mol