The answer to this question is 5a^2-6a+20+(-175a+102)over(5a^2+6a-9)
Answer:
m∠C = 66°
Step-by-step explanation:
Since AB = BD, it means this triangle is an Isosceles triangle and as such;
∠BAD = ∠BDA = 24°
Thus, since sum of angles in a triangle is 180,then;
∠ABD = 180 - (24 + 24)
∠ABD = 180 - 48
∠ABD = 132°
We are told that BC = BD.
Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC
Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.
Thus;
132 = ∠BCD + ∠BDC
Since ∠BCD = ∠BDC, then
∠BCD = ∠BDC = 132/2
∠BCD = ∠BDC = 66°
