we know that
If the distance from a converging lens to the object is less than the focal length of the lens,
then
the object is located at a location in front of the focal point
see the attached figure to better understand the problem
So
The image will always be located somewhere on the same side of the lens as the object. For such a position, the image is magnified (the image dimensions are greater than the object dimensions) and upright (if the object is right side up, then the image will also be right side up), thus allowing for easier viewing and produce a virtual image
therefore
the answer is
The image will be Virtual, upright, and larger than the object
Answer:b
Explanation:
Given
mass of heavy object is 4m
mass of lighter object is m
A person pushes each block with same force F
According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object
As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .
So the correct option is b
As we know that here no air resistance while ball is moving in air
So here we will say that
initial total energy = final total energy
here we know that
(as it will be on ground at initial and final position)
so we will say
since mass is always conserved
so we will say that final speed of the ball must be equal to the initial speed of the ball
so we have