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Rom4ik [11]
3 years ago
5

If the distance from a converging lens to the object is less than the focal length of the lens, the image will be

Physics
2 answers:
Leni [432]3 years ago
6 0

we know that

If the distance from a converging lens to the object is less than the focal length of the lens,

then

the object is located at a location in front of the focal point

see the attached figure to better understand the problem

So

The image will always be located somewhere on the same side of the lens as the object. For such a position, the image is magnified (the image dimensions are greater than the object dimensions) and upright (if the object is right side up, then the image will also be right side up), thus allowing for easier viewing and produce a virtual image

therefore

the answer is

The image will be Virtual, upright, and larger than the object

svetoff [14.1K]3 years ago
3 0
Virtual, upright, and larger than the object. :)
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A jewellery melts 500g of Silver to pour into a mould. Calculate how much energy was released as the silver solidified.
irga5000 [103]

When silver is poured into the mould the it will solidify

In this process the phase of the Silver block will change from liquid to solid.

This phase change will lead to release in heat and this heat is known as latent heat of fusion.

The formula to find the latent heat of fusion is given as

Q = mL

here given that

m = mass = 500 g

L = 111 kJ/kg

now we can find the heat released

Q = 0.5 * 111 kJ

Q = 55.5 kJ

So it will release total heat of 55.5 kJ when it will solidify

8 0
4 years ago
Which of the following will increase the resistance of a wire? Check all that apply. Check all that apply. Increasing the cross-
Lostsunrise [7]

Correct answers:

- Increasing the resistivity of the material the wire is composed of will increase the resistance of the wire.

- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

Explanation:

The resistance of a wire is given by:

R=\rho \frac{L}{A}

where

\rho is the resistitivity of the material

L is the length of the wire

A is the cross-sectional area of the wire

From the formula, we can notice that:

- The resistance (R) is directly proportional to both the resistivity (\rho) and the length of the wire (L), so when one of these quantities increases, the resistance will increase as well

- The resistance (R) is inversely proportional to the cross-sectional area (A), therefore when the resistance increases when the cross-sectional area decreases.

Based on these observations, the correct statements are:

- Increasing the resistivity of the material the wire is composed of will increase the resistance of the wire.

- Decreasing the cross-sectional area of the wire will increase the resistance of the wire.

- Increasing the length of the wire will increase the resistance of the wire.

7 0
3 years ago
A challenge gaining prominence throughout the planet is the increased need for \"green\" or sustainable energy. in certain parts
Inga [223]

32.6% of 1.4 Mw

= (0.326) x (1,400,000 joules/second)

=  456,400 joules/second .


1 year

=  (365 da) x (86,400 sec/da)  =  31,536,000 seconds


(456,000 joules/sec) x (31,536,000 sec)  =  1.438 x 10¹³ Joules 

(That's 1.438 x 10⁷ Megajoules, or 3,994,560 kWh)


5 0
4 years ago
Read 2 more answers
The largest aperture telescopes are reflectors because they require a _____ focal length.
Stells [14]
The largest aperture telescopes are reflectors because they require a shorter focal length. I think that is the answer! I hope that it helps!
5 0
3 years ago
The density of a certain type of plastic is 0.75 g/cm3 . If a sheet of this plastic is 10.0 m long, 1.0 m wide, and 1 cm thick,
Oksanka [162]

Answer:

7.5 g

Explanation:

8 0
3 years ago
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