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2 years ago

If the distance from a converging lens to the object is less than the focal length of the lens, the image will be

Physics

2 answers:

Leni [432]2 years ago

6 0

we know that

If the distance from a converging lens to the object is less than the focal length of the lens,

then

the object is located at a location in front of the focal point

see the attached figure to better understand the problem

The image will always be located somewhere on the same side of the lens as the object. For such a position, the image is magnified (the image dimensions are greater than the object dimensions) and upright (if the object is right side up, then the image will also be right side up), thus allowing for easier viewing and produce a virtual image

therefore

the answer is

The image will be Virtual, upright, and larger than the object

svetoff [14.1K]2 years ago

3 0

Virtual, upright, and larger than the object. :)

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You have been hired to design a spring-launched roller coaster that will carry two passengers per car. The car goes up a 12-m-hi

Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

$E_A} =E_{B}$

Spring potential energy =potential energy due to elevation

0.5*k*x²= mg $(h_{B}-h_{A} )$ =mgh

0.5*k*2.3²= 430*9.81*6

k=9568.92 N/m

For safety reason

k"=1.13 *k= 1.13*9568.92

k"=10812.88 N/m

agsin from conservation of energy

$E_A} =E_{C}$

spring potential energy=change in kinetic energy

0.5*k"*x²=0.5*m* $V_{max}^{2}$

10812.88 *2.3²=430* $V_{max}^{2}$

$V_{max}$ =11.53 m/s

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3 years ago

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2 years ago

Read 2 more answers

A ball has a diameter of 3.79 cm and average density of 0.0838 g/cm3.

suter [353]

Answer: 0.258 N

Explanation:

As the density of the object is much less than the density of water, it’s clear that the buoyant force, is greater than the weight of the object, which means that in normal conditions, it would float in water.

So, in order to get the ball submerged in water, we need to add a downward force, that add to the weight, in order to compensate the buoyant force, as follows:

F = Fb – Fg

Fb= δH20* 4/3*π*(d/2)³ * g

Fg = δb* 4/3*π*(d/2)³ *g

F= (δH20- δb) * 4/3*π*(d/2)³*g

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3 years ago

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3 years ago

A moving particle is subject to conservative forces only. When its kinetic energy decreases by 10 J, what happens to its mechani

satela [25.4K]

Answer:

Its mechanical energy is the same.

Explanation:

If forces are only conservative, the mechanical energy will be the same.

It can be different if energy get transformed in another kind of energy like elastic energy for example, although the amount of energy is always the same.

If we just have mechanical energy not geting transformed we have:

Em=K+U

Em: Mechanical energy

K: Kinetic energý

U: Potential energy

Then if Kinetic energy decreases 10J, Potential energy will grow up 10J to keep the same amount of mechanical energy.

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3 years ago