The car will take 300 m before it stops due to applying break.
<h3>What's the relation between initial velocity, final velocity, acceleration and distance?</h3>
- As per Newton's equation of motion, V² - U² = 2aS
- V= final velocity velocity of the object, U = initial velocity velocity of the object, a= acceleration, S = distance covered by the object
- Here, U = 60 ft/sec, V = 0 m/s, a= -6 ft/sec²
- So, 0² - 60² = 2×6× S
=> -3600 = -12S
=> S = 3600/12 = 300 m
Thus, we can conclude that the distance covered by the car is 300 m before it stopped.
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Question: A car is being driven at a rate of 60 ft/sec when the brakes are applied. The car decelerates at a constant rate of 6 ft/sec². How long will it take before the car stops?
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Answer:
Natural science is concerned with the description, prediction, and understanding of natural phenomena based on empirical evidence from observation and experimentation. It can be divided into two main branches: life science (or biological science) and physical science.
Explanation:
I'm not too sure but I think it's nuclear decay
Answer:
Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.
Explanation:
Answer:
Weight on Earth = We = 186.2 N
Weight on Mars = Wm = 70.94 N
Explanation:
The weight of an object is defined as the force applied on the object by the gravitational field. The magnitude of weight is given by the following formula:
W = mg
were,
W= Weight of Eric
m = mass of Eric
g = acceleration due to gravity
ON EARTH:
W = We = Eric's Weight on Earth = ?
m = Eric's Mass on Earth = 19 kg
ge = acceleration due to gravity on Earth = 9.8 m/s²
Therefore,
We = (19 kg)(9.8 m/s²)
<u>We = 186.2 N</u>
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ON MARS:
W = Wm = Eric's Weight on Mars = ?
m = Eric's Mass on Mars = 19 kg
gm = acceleration due to gravity on Mars = 0.381(ge) = (0.381)9.8 m/s² = 3.733 m/s²
Therefore,
Wm = (19 kg)(3.733 m/s²)
<u>Wm = 70.94 N</u>