To be able to determine the original speed of the car, we use kinematic equations to relate the acceleration, distance and the original speed of the car moving.
First, we manipulate the one of the kinematic equations
v^2 = v0^2 + 2 (a) (x) where v = 0 since the car stopped
Writing the equation in such a way that the initial velocity or v0 is written on one side of the equation,
<span>we get v0 = sqrt (2(a)(x))
Substituting the known values,
v0 = sqrt(2(3.50)(30.0))
v0 = 14.49 m/s
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Therefore, before stopping the car the original speed of the car would be 14.49 m/s
Floating. When you have no gravity you have nothing to be pushing you down to the floor so that would be an example of no gravity pushing on you.
Answer:
b. 40V , 40V
Explanation:
Connections are as per the figure.
As total current through source is 4A , current through each lamp is 1A.
As total resistance of the circuit is 10Ω ,resistance of each bulb is 40Ω because in case of a parallel circuit in which identical objects are connected ,
where R is the resistance of each bulb and n is the number of bulbs.
As per Ohm's law , voltage of the source =IR = 4×10 =40V.
We can see from the figure that if the voltage across the source is 40V , the voltage across each bulb is also 40V.