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Roman55 [17]
3 years ago
15

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water

Chemistry
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

Mass = 48 g

Explanation:

Given data:

Number of moles of H₂ react= 3.00 mol

Number of moles of O₂ react= 1.50 mol

Number of moles of water formed = 3.00 mol

Mass of oxygen react = ?

Solution:

Chemical equation:

2H₂ + O₂    →      2H₂O

It is stated in given question when 1.50 moles of oxygen react 3.00 moles of water are formed. Thus, mass of 1.50 moles of oxygen is

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 1.50 mol × 32 g/mol

Mass = 48 g

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Calculate the mole fraction of kbr (molar mass 119.00 g/mol) in a solution made by dissolving 0.30 g kbr in 0.400 l of H2O (d =
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The mole fraction of KBr in the solution is 0.0001

<h3>How to determine the mole of water</h3>

We'll begin by calculating the mass of the water. This can be obtained as follow:

  • Volume of water = 0.4 L = 0.4 × 1000 = 400 mL
  • Density of water = 1 g/mL
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Density = mass / volume

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Croiss multiply

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Finally, we shall determine the mole of the water

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  • Mole of water = ?

Mole = mass / molar mass

Mole of water = 400 / 18.02

Mole of water = 22.2 moles

<h3>How to de terminethe mole of KBr</h3>
  • Mass of KBr = 0.3 g
  • Molar mass of KBr = 119 g/mol
  • Mole of KBr = ?

Mole = mass / molar mass

Mole of KBr = 0.3 / 119

Mole of KBr = 0.0025 mole

<h3>How to determine the mole fraction of KBr</h3>
  • Mole of KBr = 0.0025 mole
  • Mole of water = 22.2 moles
  • Total mole = 0.0025 + 22.2 = 22.2025 moles
  • Mole fraction of KBr =?

Mole fraction = mole / total mole

Mole fraction of KBr = 0.0025 / 22.2025

Mole fraction of KBr = 0.0001

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brainly.com/question/2769009

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