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Maurinko [17]
3 years ago
10

Why are rocks important to geologists? Check all that apply.

Physics
2 answers:
Lemur [1.5K]3 years ago
7 0

Answer:

a, b and c or They give clues about Earth's past environments.

They contain valuable resources used for building.

They present opportunities for future use in technology.

Explanation:

levacccp [35]3 years ago
3 0

Answer:

They give clues about Earth's past environments.

They contain valuable resources used for building.

Explanation:

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Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; both students move away from each
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forcing in act

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What is an example of a form of friction that impedes motion
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to me I think is static

Explanation:

that is my own thinking

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If we wanted to describe and better understand the structure of the rings of Saturn, we might develop a
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The Greek philosopher Aristotle and the Roman Catholic Church also believed the sun revolved around the earth. In 1543, Nicolaus Copernicus<span> published a new theory stating the earth revolves around the sun. This is known as the Copernican theory.</span>
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3 years ago
I need help!! i’ll give 20 points
larisa86 [58]

Answer:

780 m to travel north

Explanation:

6 m over = 750

53 degree so it will take about 2 min to reach the destination

8 0
3 years ago
a whistle you use to call your hunting dog has a frequency of 21 khz, but your dog is ignoring it. you suspect the whistle may n
laila [671]

To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as

f = f_0 (\frac{v-v_0}{v})

Here,

f_0 = Original frequency

v_0 = Velocity of the observer

v = Velocity of the speed

Our values are,

v = 340m/s \rightarrow \text{Speed of sound}

f = 20kHz \rightarrow \text{Apparent frequency}

f_0 = 21kHz \rightarrow \text{Original frequency}

Using the previous equation,

f = f_0 (\frac{v-v_0}{v})

Rearrange to find the velocity of the observer

v_0 =v (1-\frac{f}{f_0})

Replacing we have that

v_0= (340m/s)(1-\frac{20kHz}{21kHz})

v_0 = 16.19m/s

Therefore the velocity of the observer is 16.2m/s

4 0
3 years ago
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