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oksano4ka [1.4K]
3 years ago
5

Which statement is true about the technology used to improve the motion of space vehicles on rough surfaces?

Physics
1 answer:
Andrei [34K]3 years ago
4 0

The correct answer is C.)

It has made road vehicles safer because magnetometers are used to detect particles found in radiation emitted during combustion of fuel.

h a v e  a  g r e a t  d a y

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If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity lev
nekit [7.7K]

Answer:

(c) 97 dB sound intensity level

Explanation:

We have given the intensity of the loud car horn I=0.005w/m^2

We know that I_O=10^{-12}w/m^2

Now the sound intensity level is given by \beta =10log\frac{I}{I_0}=10log\frac{0.005}{10^{-12}}=96.98dB , which is nearly equal to 97

So the sound intensity level will be 97 dB

So option (c) will be the correct option

4 0
3 years ago
Water from a vertical pipe emerges as a 10-cm-diameter cylinder and falls straight down 7.5 m into a bucket. The water exits the
cupoosta [38]

The diameter of the column of the water as it hits the bucket is 4.04 cm

The equation of continuity occurs in the fluid system and it asserts that the inflow and the outflow of the volume rate at the inlet and at the outlet of the system are equal.

By using the kinematics equation to determine the speed of the water in the bucket and applying the equation of continuity to estimate the diameter of the column, we have the following;

Using the kinematics equation:

\mathbf{v_f ^2 = v_i^2 + 2gh}

\mathbf{v_f ^2 =(2.0)^2 + 2\times 9.8 \times 7.5}

\mathbf{v_f ^2 =151 m/s}

\mathbf{v_f  =\sqrt{151 m/s}}

\mathbf{v_f  =12.29 \ m/s}  

From the equation of continuity:

\mathbf{A_iV_i = A_fV_f}

\mathbf{\pi r^2_iV_i = \pi r^2_fV_f}

\mathbf{ r^2_iV_i =  r^2_fV_f}

\mathbf{ (\dfrac{10}{2})^2\times 2.0 =  r_f^2 \times 12.29}

\mathbf{ 50 = 12.29 \times r_f^2}

\mathbf{ r_f=  \sqrt{\dfrac{50}{12.29} }}

\mathbf{ V_f= 2.02 \ cm }

Since diameter = 2r;

∴

The diameter of the column of the water is:

= 2(2.02) cm

= 4.04 cm

Learn more about the equation of continuity here:

brainly.com/question/10822213

6 0
2 years ago
an empty propane tank dropped from a hot air balloon hits the ground with a speed of 143.8 m/s. from what height was the tank re
vodomira [7]
What you know:
Vi=0m/s
Vf=143.8m/s
A=-9.8m/s
d=???
Use the equation Vf^2=Vi^2+2A(d)
Rearrange to isolate d: d=Vf^2/2A
d=(143.8)^2/2(-9.8)
d=20678.4/-19.6
d=-1055m
The tank was released from a height of 1055m
8 0
3 years ago
PLEASE HELP. NOTICE HOW THEY PUT FUTURE
MrMuchimi

I think its <u>B</u> because it looks like it might indicate a future rain storm.

6 0
3 years ago
The velocity of a particle moving along the x-axis varies with time according to v(t) = A + Bt−1 , where A = 2 m/s, B = 0.25 m,
kondaur [170]

Answer:

a= -2\ m/s^2

a=-12.5\ m/s^2

x=2.17 m

x=8.4 m

Explanation:

Given that

v=A+Bt^{-1}

v=2+0.25t^{-1}

To find acceleration :

we know that

a=\dfrac{dv}{dt}

\dfrac{dv}{dt}=0-0.5t^{-2}

a=-0.5t^{-2}

Acceleration at t= 2 s

a=-0.5\times 2^{-2}

a= -2\ m/s^2

Acceleration at t= 5 s

a=-0.5\times 5^{-2}

a=-12.5\ m/s^2

We know that

v=\dfrac{dx}{dt}

dx=\left(2+\dfrac{1}{4t}\right)dt

Position at t= 2 s:

\int_{0}^{x}dx=\int_{1}^{2} \left(2+0.25\dfrac{1}{t}\right)dt

x=\left [2t+0.25\ lnt \right ]_{1}^{2}

x=2+0.25 ln2

x=2.17 m

Position at t= 5 s:

\int_{0}^{x}dx=\int_{1}^{5} \left(2+0.25\dfrac{1}{t}\right)dt

x=\left [2t+0.25\ lnt \right ]_{1}^{5}

x=8+0.25 ln5

x=8.4 m

4 0
2 years ago
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