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Crank
3 years ago
8

Identify the stage in cellular respiration that produces carbon dioxide as a waste product

Physics
1 answer:
ollegr [7]3 years ago
6 0
During cellular respiration, organisms use oxygen to turn glucose into carbon dioxide, water, and energy in the form of ATP. The process has three stages: glycolysis , the Krebs cycle, and the electron transport chain. Glycolysis in the cytoplasm ), breaks down 1 glucose into 2 pyruvate and 2 ATP. The Krebs cycle (in the mitochondrion's matrix), provides the hydrogen and electrons needed for the electron transport chain. Another 2 are formed here. The electron transport chain (on the inner mitochondrial membrane) forms 32 ATP through oxidative phosphorylation .
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In the graph below, why does the graph stop increasing after 30 seconds?
stepladder [879]

Answer:

The answer is "Option C".

Explanation:

It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.

hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.

A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.

6 0
3 years ago
Two long, parallel wires are attracted to each other by a force per unit length of 350 µN/m. One wire carries a current of 22.5
pishuonlain [190]

Answer

given,

force per unit length = 350 µN/m

current, I = 22.5 A

y = y = 0.420 m

\dfrac{F}{L}= \dfrac{KI_1I_2}{d}

I_2 = \dfrac{F}{L}\dfrac{d}{KI_1}

I_2 = 350\times 10^{-6}\times \dfrac{0.42}{2 \times 10^{-7}\times 22.5}

    I₂ = 32.67 A

distance where the magnetic field is zero

\dfrac{4\pi \times 10^{-7}\times 32.67}{2\pi y_1}=\dfrac{4\pi \times 10^{-7}\times 22.5}{2\pi (0.42-y_1)}

y_1 = 0.248\ m

there the distance at which the magnetic field is zero in the two wire is at 0.248 m.

3 0
3 years ago
Please help!
Trava [24]

Answer:

3 N to the right

Explanation:

There are two forces acting on the car:

- A force of 10 N towards the right

- A force of 7 N towards the left

Therefore, the net force is given by the difference between the two, since they are in opposite directions:

F=10 N-7 N=3 N

And the direction is to the right, since the force to the right has greater magnitude than the force to the left.

7 0
3 years ago
Read 2 more answers
a car moving with a speed of 10 metre per second is accelerator at the rate of 2 metre per second square find its velocity after
STatiana [176]

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

7 0
3 years ago
Compared to the charge on a proton, the amount of charge on an electron is,
lbvjy [14]
Compared to the charge on a proton, the amount of charge on an electron is same and has the opposite sign
3 0
4 years ago
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