1950 g This is the answer due to the kilograms of lead being distributed
The acceleration and distance is related to the following expression:
y=v0*t + a*t^2/2 ; v0=0
y=44.1*100/2 = 2205m
hence, the speed will be
v=0 + a*t = 441m/s
from that height it will just be subjected to the gravitational acceleration
0=v_acc^2 -2g*y_free
y_free = v_acc^2/2g = 9922.5m
<span>y_max = y_acc+y_free = 441+9922.5 =10363.5m</span>
Answer:
= 33.33 cm
Explanation:
Given:
When mass,
=21 kg
distance travelled is
= 140 cm
When mass,
=5 kg
distance travelled is
= ?
Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.
Therefore according to the question,


= 33.33 cm
Distance travelled is 33.33 cm when mass is 5 kg.