Answer:

Explanation:
Given:
- mass of solid disk,

- radius of disk,

- force of push applied to disk,

- distance of application of force from the center,

<em>For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

where:
= static frictional force




For a Rectangular plate has a voltage of +180V and a 'voltage of -5V. , the second plate has the Electric field mathematically given as
E=21.5*10^3v/m
<h3>What is
the field strength?</h3>
Generally, the equation for the Electric field is mathematically given as
E=v/d
Where
v={180-(-5)}v
v=185v
Therefore
E=185/8.6*10^{-3}
E=21.5*10^3v/m
In conclusion, Electric field
E=21.5*10^3v/m
Read more about electric field
brainly.com/question/9383604
Henry Moseley, its a generator which uses energy to generate electricity
Answer:
a. Approximate umber of atoms = 10¹¹
b. number of atoms = 50 atoms thick
Note: The question is missing some parts. The complete question is as follows; Calculate the approximate number of atoms in a bacterium. Assume that the average mass of an atom in the bacterium is ten times the mass of a hydrogen atom. (Hint: The mass of a hydrogen atom is on the order of 1×10⁻²⁷ kg and the mass of a bacterium is on the order of 1×10⁻¹⁵ kg)
Explanation:
a. Approximate umber of atoms = mass of bacterium / 10 * mass of hydrogen
number of atoms = 10⁻⁵/ 10 × 10⁻²⁷
number of atoms = 10¹¹ atoms
b. The cell membrane is 10-8 m thick while the hydrogen atom has a diameter of 10-10 m.
The number of atoms in the cell membrane = d1 / 2 × d2
where d1 = diameter of cell membrane; d2 = diameter of hydrogen atom
The number of atoms in the cell membrane = 10⁻ / 2 × 10⁻¹⁰ = 50 atoms
Answer:
To survive, every cell must have a constant supply of vital substances such as sugar, minerals, and oxygen, and dispose of waste products, all carried back and forth by the blood cells. Without these substances, cells would die in a very short period of time.
Explanation: