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andre [41]
3 years ago
8

If a system absorbs heat and also does work on its surroundings its energy

Physics
1 answer:
VashaNatasha [74]3 years ago
7 0
This is, I think, about heat engines and the first law of thermo ?Hot reservoir supplies heat to the system at a high temperature. System does work.System rejects some heat to a cold reservoir at a low temperature.That's a word description of a thermo block diagram. And I think it refers to the "steady state". Seems reasonable that the system would have to warm up (car engines, eg), during which process the (internal ?) energy would presumably rise. In the steady state, however, the energy will presumably be constant. If it continued to rise ... the thing would overheat ????
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The magnitude of the angular momentum of the rod immediately after the collision is given as (pf + pi) * d. (Option A).

<h3>What is Angular Momentum?</h3>

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The formula for Angular Momentum is given as:

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brainly.com/question/4126751

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3 0
2 years ago
How do we know Earth is spinning, not the Sun?
Tpy6a [65]

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Because it is said that the earth rotates and revolves around the sun and moon so it is impossible for the earth not to be spinning.

Explanation:

4 0
3 years ago
Sam is pulling a box up to the second story of his apartment via a string. The box weighs 16.5 kg and starts from rest on the gr
Katyanochek1 [597]

Answer:

Weight (mass) = 16.5 kg

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acceleration =2.6 m/s^2

displacement = 13.2m

now,

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8 0
3 years ago
In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
Tcecarenko [31]

Answer:

The amount of heat transfer is 21,000J .

Explanation:

The equation form of thermodynamics is,

ΔQ=ΔU+W

Here, ΔQ is the heat transferred, ΔU is the change in internal energy, and W is the work done.

Substitute 0 J for W and 0 J for ΔU

ΔQ = 0J+0J

ΔQ = 0J

The change in internal energy is equal to zero because the temperature changes of the house didn’t change. The work done is zero because the volume did not change

The heat transfer is,

ΔQ=Q  (in ) −Q (out )

Substitute 19000 J + 2000 J for Q(in)  and 0 J for Q(out)

ΔQ=(19000J+2000J)−(0J)

=21,000J

​Thus, the amount of heat transfer is 21,000J .

​

8 0
3 years ago
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