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4 years ago

If a system absorbs heat and also does work on its surroundings its energy

1 answer:

7 0

This is, I think, about heat engines and the first law of thermo ?Hot reservoir supplies heat to the system at a high temperature. System does work.System rejects some heat to a cold reservoir at a low temperature.That's a word description of a thermo block diagram. And I think it refers to the "steady state". Seems reasonable that the system would have to warm up (car engines, eg), during which process the (internal ?) energy would presumably rise. In the steady state, however, the energy will presumably be constant. If it continued to rise ... the thing would overheat ????

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Glacial episodes are an example of

ira [324]

They are an example of a positive feedback.

5 0

3 years ago

A sample of nitrogen occupies 5.50 liters under a pressure of 900 torr at 25oC. At what temperature will it occupy 10.0 liters a

vitfil [10]

Answer:

At 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.

Explanation:

Given:

Volume of a sample of nitrogen = 5.50 liters

Pressure = 900 torr

Temperature = 25°C

To find the temperature at which the nitrogen will occupy 10 liters volume at same pressure.

Solution:

Since the pressure is kept constant, so we can apply the temperature-volume law also called the Charles Law.

Charles Law states that the volume of a gas held at constant pressure is directly proportional to the temperature of the gas in Kelvin.

Thus, we have :

$V$ ∝ $T$

$\frac{V}{T}=k$

where $k$ is a constant.

For two samples of gases, the law can be given as:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

From the data given:

$V_1=5.5\ l$

$T_1=25\ \°C =(273+25)K= 298 K$

$V_2=10\ l$

We need to find $T_2$ .

Plugging in values in the formula.

$\frac{5.5}{298}=\frac{10}{T_2}$

Multiplying both sides by $T_2$ .

$T_2\times\frac{5.5}{298}=\frac{10}{T_2}\times T_2$

$\frac{5.5}{298}T_2={10}$

Multiplying both sides by $\frac{298}{5.5}$

$\frac{298}{5.5}\times\frac{5.5}{298}T_2=\frac{10\times 298}{5.5}$

$T_2=541.82\ K$

$T_2=541.82\ K-273\ K = 268.82\°C$

Thus, at 268.82°C volume occupied by nitrogen is 10 liters at pressure of 900 torr.

7 0

3 years ago

Pooping in my room and my room is upstairs and upstairs bathroom upstairs

diamong [38]

Answer:

huh? do you need help on math?

Explanation:

what do you mean?

7 0

2 years ago

A 77.0−kg short-track ice skater is racing at a speed of 12.6 m/s when he falls down and slides across the ice into a padded wal

sukhopar [10]

Answer:

-6112.26 J

Explanation:

The initial kinetic energy, $KE_i$ is given by

$KE_i=0.5mv_1^{2$ } where m is the mass of a body and $v_i$ is the initial velocity

The final kinetic energy, $KE_f$ is given by

$KE_f=0.5mv_f^{2}$ where $v_f$ is the final velocity

Change in kinetic energy, $\triangle KE$ is given by

$\triangle KE=KE_f-KE_i=0.5mv_f^{2}-0.5mv_1^{2}=0.5m(v_f^{2}-v_i^{2})$

Since the skater finally comes to rest, the final velocity is zero. Substituting 0 for $v_f$ and 12.6 m/s for $v_i$ and 77 Kg for m we obtain

$\triangle KE=0.5*77*0^{2}-0.5*77*(0^{2}-12.6^{2})=-6112.26 J$

From work energy theorem, work done by a force is equal to the change in kinetic energy hence for this case work done equals -6112.26 J

3 0

3 years ago

How long will it take a horse to go from rest to 19 km/hr if it is accelerating at 5 km/hr 2 ?

Nataliya [291]

Answer:

I attached a PFD with the answer to your question and roughly 50 others involving acceleration and how to calculate it. This PDF gives you the answers to all the question whilst showing you an in-depth explanation on how they got the answer. Hopefully that helps

Explanation:

May I have brainliest please? :)

Download pdf

6 0

3 years ago