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VARVARA [1.3K]
2 years ago
11

When a funnel shaped cloud considered as a tornado?

Physics
1 answer:
gladu [14]2 years ago
3 0
It has to be one continuous column of cloud (air) connected to the ground and in constant rotation.
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A ____________ galaxy has arms of gas and dust; where as _____________ galaxy is a category of galaxy that does not have a disti
Jet001 [13]

Answer:

spiral, an irregular

Explanation:

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How are thunderstorms kept alive?
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2 years ago
There is a 3-kg toy cart moving at 4 m/s. Calculate the kinetic<br> energy of the cart.
m_a_m_a [10]

The kinetic energy of the cart is 24 J.

<u>Explanation:</u>

The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.  

The kinetic energy is the given by,

                           K.E = 1/2 mv^2

Given the mass m = 3 kg,        v = 4 m / s.

                            K.E = 1/2 \times 3 \times (4)^2          

                          K.E  = 24 J.

5 0
2 years ago
What is the final position of an object that travel 5 meters/ second for 10 seconds?
Naddik [55]

Answer:

velocity =  \frac{displacement}{time}  \\ displacement = velocity \times time \\  = 5 \times 10 = 50meter \\ thank \: you

4 0
2 years ago
Block with m = 300 grams oscillates at the end of a linear spring with k = 6.5 N/m. (assume this is a top-down view and the bloc
masha68 [24]

Explanation:

Given that,

Mass of the block, m = 300 g = 0.3 kg

Linear spring constant, k = 6.5 N/m

(a) Let T is the period of the block's motion. It is given by :

T=\dfrac{2\pi}{\omega}

where

\omega=\sqrt{\dfrac{k}{m}}= angular frequency

Also, \omega=\sqrt{\dfrac{k}{m}}

T=\dfrac{2\pi}{\sqrt{\dfrac{k}{m}}}

T=\dfrac{2\pi}{\sqrt{\dfrac{6.5}{0.3}}}

T = 1.34 seconds

(b) The maximum acceleration of the block is, a_{max}=2\ m/s^2

The maximum acceleration is given by :

a_{max}=\omega^2A

A is the amplitude of the motion,

A=\dfrac{a_{max}}{\omega^2}

A=\dfrac{a_{max}}{(\sqrt{\dfrac{k}{m}})^2}

A=\dfrac{ma_{max}}{k}

A=\dfrac{0.3\times 2}{6.5}

A = 0.09 meters

Hence, this is the required solution.

3 0
3 years ago
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