Question

What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2? express your answer in kilograms to one decimal place?

Answer 1

Answer: Equation: N2(g) + 3H2(g) → 2NH3(g) Check for limiting reactant Molar mass N2 = 28g/mol mol N2 in 31,500g = 31,500/28 = 1,125 mol N2 This will require 1,125*3 = 3,375 mol H2 Molar mass H2 = 2g/mol Mol H2 in 5,220g = 5,220/2 = 2,610 mol H2 The H2 is limiting From the equation: 3 mol H2 will produce 2mol NH3 2610 mol H2 will produce 2610*2/3 = 1,740 mol NH3 Molar mass NH3 = 17g/mol Mass of 1740 mol NH3 = 1740*17 = 29,580g NH3 produced Mass of NH3 produced = 29.6kg