Answer:
3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
The coefficients are 3, 1, 3, 1
Explanation:
From the question given above, the following data were:
Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:
AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄
The above equation can be balanced as follow:
AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄
There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 3 in front of NaCl as shown below:
AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
There are 3 atoms of Cl on the right side and 1 atom on the left. It can be balance by putting 3 in front of AgCl as shown below:
3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄
Thus, the equation is balanced.
The coefficients are 3, 1, 3, 1
The receive very little rainfall
I think the answer for this is 4702.5 J/g*k Depending on if it is water as a solid liquid or gas. I used water as a liquid when I solved it. J=(75g)(4.18 J/g*k)(15K)
Answer:
V = 552 mL or 0.552 L
Explanation:
First, we need to calculate the number of moles of H2 using the ideal gas equation which is:
PV = nRT
Solving for n:
n = PV / RT
Where:
P = Pressure
V = Volume
R = Gas constant (0.082 L atm / K mol)
T = Temperature in K
Let's convert first both pressure in atm, remember that 1 atm = 760 mmHg
P = 735 / 760 = 0.967 atm
Pwater = 21 / 760 = 0.028 atm
Finally temperature to Kelvin:
T = 23 + 273.15 = 296.15 K
Now, at first the hydrogen was collected by water displacement so pressure is:
P = 0.967 - 0.028 = 0.939 atm
Now the moles of hydrogen:
n = 0.939 * 0.568 / 0.082 * 296.15
n = 0.022 moles
Now that we have the moles, let's calculate the volume when the pressure is 735 mmHg
V = nRT/P
V = 0.022 * 0.082 * 296.15 / 0.967
V = 0.552 L or 552 mL
This is the volume that hydrogen occupies.
