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hjlf
3 years ago
10

Where does oxidation occur in an electrochemical cell?

Chemistry
2 answers:
AlladinOne [14]3 years ago
8 0
Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell

Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.

The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.
sweet [91]3 years ago
8 0

Answer : The correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.

Explanation :

As we know that there are two types of cell which are, electrolytic cell and electrochemical cell or galvanic cell.

Electrolytic cell : It is defined as the cell in which the chemical reaction occurs by passing of the current from external source.

In this electrolytic cell, the oxidation occurs at anode which is a positive electrode and reduction occurs at cathode which is a negative electrode.

Electrochemical cell : It is defined as the cell in which the chemical reaction occurs with the production of electric potential difference between the two electrodes.  It is also known as voltaic cell.

In this cell, the oxidation occurs at anode which is a negative electrode and reduction occurs at cathode which is a positive electrode.

From this we conclude that, the oxidation occurs at the anode in both an electrolytic cell and a voltaic cell.

Hence, the correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.

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The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
Which statement about entropy is correct? - Entropy is sometimes described as the degree of randomness in a system. - solids are
marysya [2.9K]

Answer: Entropy is sometimes described as the degree of randomness in a system.

4 0
2 years ago
Rewrite and Balance the Equation <br> N₂ + H₂ -&gt; NH3
Mars2501 [29]

Answer:N

2

+ 3

H

2

-----> 2N

H

3

Explanation:

N

2

+

H

2

-----> N

H

3

Let us balance this equation by counting the number of atoms on both sides of the arrow.

N

2

+

H

2

-----> N

H

3

N=2 , H=2 N=1, H=3

To balance the number of N atom on Right Hand Side (RHS) , I will add one molecule of N

H

3

on RHS

N

2

+

H

2

-----> 2N

H

3

N=2 , H=2 N=2 , H= 6

To balance the number of H atoms on Left Hand Side (LHS) , I will add two molecules of

H

2

on LHS

N

2

+ 3

H

2

-----> 2N

H

3

N=2 , H=6 N=2 , H= 6

Answer link

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4 0
3 years ago
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Which of the following compounds will experience dipole-dipole forces of attraction?
ddd [48]
NaCl and H2S will experience dipole-dipole interaction because they are permanently polarized.
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Write the molecular formula for the following compound.<br>​
Sholpan [36]

Answer : The molecular formula of the compound is, C_8H_9O_3N

Explanation :

Molecular formula : It is the representation of substance by the symbols and it denotes the number of atoms of each element present in the compound.

Now count the number of carbon, hydrogen, nitrogen and oxygen atoms present in the given compound.

As we see that in the given compound, there are 8 atoms of carbon element, 3 atoms of oxygen element, 1 atom of nitrogen element, 9 atoms of hydrogen element.

Thus, the molecular formula of the compound will be C_8H_9O_3N

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