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deff fn [24]
4 years ago
11

Based on VSEPR theory and your observations from the Molecular Geometry lab consider the following questions What is the predict

ed hybridization at an atom which is surrounded by a double bond and two single bonds?
a) Sp
b) sp^2
c) sp^3
Chemistry
1 answer:
____ [38]4 years ago
6 0

Answer:

b) sp^2

Explanation:

Hybridization refers to the concept that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties. In chemistry, orbital hybridisation (or hybridization) is the implies the mixing of atomic orbitals to form hybrid orbitals (with different energies, shapes, etc., different from that of the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds according to the principles of the valence bond theory.

In 1931 Linus Pauling proposed the idea of “mixing” the orbitals or “hybridizing” them to account for certain observed bonding patterns. Pauling proposed a sort of a combination of the orbitals giving you an orbital that has partial characters.

Hybridization is merely a mathematical construct. It is never an actual “process” that occurs within orbitals . Hybridization is a mathematical model that describes how the atomic orbitals would’ve looked like based on the observable molecular orbitals.

sp2 hybridization leads to the formation of a double bond. sigma bonds may also be formed depending on the valency of the central atom. In alkenes, an sp2 hybridized carbon atom forms a double bond in addition to two sigma bonds to other atoms.

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Answer:

Even the most powerful light-focusing microscopes can't visualise single atoms. What makes an object visible is the way it deflects visible light waves. Atoms are so much smaller than the wavelength of visible light that the two don't really interact. To put it another way, atoms are invisible to light itself.

Explanation:

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3 years ago
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Toxicants generally follow the laws of ________, moving from areas of high concentration to areas of lower concentration
zloy xaker [14]

Toxicants generally follow the Law of Diffusion , moving from areas of high concentration to areas of lower concentration.

<h3><u>What are Toxicants ?</u></h3>

Any hazardous chemical is a toxicant. Both naturally occurring and artificial toxicants have the potential to be harmful. A toxin, in contrast, is a poison created spontaneously by an organism (e.g. plant, animal, insect). The many toxicant categories may be present in the air, land, water, or food.

A substance is toxic if it has the potential to be harmful or have negative effects on health. Chemicals like polychlorinated biphenyls (PCBs) and dioxin, which are present at some hazardous waste sites, often cause people to worry.

<h3><u>What is the Law of Diffusion ?</u></h3>

Graham's law of diffusion states that the ratio of the diffusion rate of two gases is the same as the ratio of the square root of the molar mass of the gases.

To view more questions about Toxicants, refer to: brainly.com/question/5896648

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8 0
1 year ago
How many milliliters of 0. 0140 m na2s2o3 solution are needed to dissolve 0. 590 g of agbr? agbr(s) 2na2s2o3(aq)→na3ag(s2o3)2(aq
Marina86 [1]

The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.

<h3>What is molarity?</h3>

Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.

Given,

Molarity of Sodium thiosulfate = 0.0140 M

Mass of solute (AgBr) = 0.590 gm

Molar mass of AgBr = 187.77 g/mol

First moles from the mass can be calculated as,

Moles = mass ÷ molar mass

n = 0.590 g ÷ 187.77 g/mol

= 0.00314 moles

Now, the volume of the solution from molarity is calculated as,

Volume = moles ÷ molarity

= 0.00314 moles ÷ 0.0140

= 0.225 L

Therefore, 225 mL is the volume required.

Learn more about molarity here:

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3 0
2 years ago
What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

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3 years ago
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Gelneren [198K]

Answer:

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Explanation:

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3 0
3 years ago
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