Answer:
Explanation:
As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)
ΔG = ΔG° + RTInQ
Q = 1
ΔG = ΔG°
ΔG = =nFE°
n=no of electrons transfered.
E° = 1.1v
ΔG° = -2 * 96500 * 1.10
= -212300J
ΔG° =-212.3kJ/mol
<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>
Answer:
893 moles
Explanation:
An ideal gas at STP occupies 22.4 liters. Calculating Oxygen as if it were an ideal gas there are . 893 moles of Oxygen in 20.0 liters.
Answer:
26.74g
Explanation:
The equation of the reaction is;
SIO₂ + 3C --> SiC +2CO
From the balanced equation, the relationship between SiC and C is;
3 mol of C produces 1 mol of SiC
Converting mol to mass using; Mass = moles * Molar mass
Mass of SiC = 1 mol * 40.11 g/mol = 40.11g
This means;
3 mol of C produces 40.11g of SiC
2 mol of C produces xg of SiC
3 = 40.11
2 = x
x = 2 * 40.11 / 3 = 26.74g
Answer:
One positive charge
Explanation:
In a neutral atom, the number of positive and negative particles are equal. This leaves the atom with a net charge of zero, 0.
When the number of protons in an atom is greater than the number of electrons, the atom becomes positively charged. When an atom loses an electron when a bond wants to form, it has a net positive charge.
The number of electrons lost or gained determines the charge.
<h3>
Answer:</h3>
51.93 L
<h3>
Explanation:</h3>
From the question we are given the following components of an ideal gas;
Number of moles = 21.5 mol
Pressure, P = 9.65 atm
Temperature, T = 10.90°C, but K= °C + 273.15
=284.05 k
We are required to calculate the volume of the ideal gas.
We are going to use the ideal gas equation which is given by;
PV = nRT, where P, V, T and n are the pressure, volume, temperature and moles of the ideal gas respectively. R is the ideal gas constant, 0.082057 L.atm/mol.K
To get the volume, we rearrange the formula to get;
V = nRT ÷ P
= (21.5 × 0.082057 × 284.05 K) ÷ 9.65 atm
= 51.93 L
Thus, the volume of the ideal gas is 51.93 L
