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sp2606 [1]
3 years ago
10

Acidic substances will taste _____

Chemistry
1 answer:
choli [55]3 years ago
5 0

Answer:False, we can sense four tastes, namely salty, sweet, sour and bitter. Acids taste sour. If we want to know if something is an acid, we can just taste it.

Explanation:

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You throw a ball straight up in the air trying to throw it as high as possible. What do you think happens to the balls kinetic e
mote1985 [20]
With the info given i would have to say their is no kinetic energy, it's all potential energy.
6 0
3 years ago
The freezing point of water in degrees Celsius is [ Select ] __________. The freezing point of water in degrees Fahrenheit is [
ElenaW [278]

Answer: 0, 32 , 273

Explanation:

The freezing point of water in degree Celsius, Fahrenheit and Kelvin are in the following order;   0  , 32  , 273

4 0
3 years ago
The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate
Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8 cm

for a BCC structure, the atomic radius is equal to

r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3}  }{4}=2.3103x10^{-8}cm

7 0
3 years ago
Suppose you have a 2.0 molar solution of sodium hydroxide (naoh), and you need 65 ml of 0.6 molar naoh. how should you make this
nalin [4]

The given molarity of sodium hydroxide solution = 2.0 M

The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH

Converting 65 mL to L:

65mL*\frac{1L}{1000mL} =0.065L

Calculating the moles of NaOH in the final solution:

0.065L * \frac{0.6 mol}{L} =0.039mol

Finding out the volume of 2.0 M solution taken to prepare the final solution:

0.039 mol * \frac{1L}{2.0mol}=0.0195L*\frac{1000mL}{1L} =19.5mL

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.


3 0
3 years ago
A diatomic molecule with a triple covalent bond is
Debora [2.8K]
The diatomic molecule with a triple covalent bond is N2.
Nitrogen has five atoms in its valence shell. In order for it to attain the octet structure, that is, to have eight electrons in its outermost shell, it has to donate three electrons, just like the other element it is reacting with in order to form a triple covalent bond.
5 0
3 years ago
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