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ycow [4]
3 years ago
10

Which of the following equations is NOT balanced properly? Which of the following equations is NOT balanced properly? Cr2(SO4)3

+ 6KOH → 2Cr(OH)3 + 3 K2SO4 2NaHCO3 → Na2CO3 + CO2 + H2O 4NH3 + 14O2 → 4NO2 + 6H2O 2Cr + 6HCl → 2CrCl3 + 3H2 none of the above
Chemistry
1 answer:
tangare [24]3 years ago
7 0

Answer:

Balancing of equation involves making sure the number of atoms of an element on the left hand side(reactant) is equal to the number of atoms of an element on the right hand side(product)

4NH3 + 14O2 → 4NO2 + 6H2O

In the equation above,the number of Oxygen on the left is (14*2)=28 while the number of oxygen on the right is (4*2+6)=14. This makes it an unbalanced equation.

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How many atoms make up a diatomic molecule?
zalisa [80]
The prefix 'di' means two. Hence two atoms make up a diatomic molecule.
Hope this helps!
6 0
3 years ago
Which particle diagram represents a mixture of three substances
Anni [7]

Following the key in the diagram (see the attached image), the only particle diagram that represents a mixture of three substances is diagram 2.

To simplify it, let us replace the key in the diagram as follows;

  1. atom of one element = A
  2. atom of different element = B

Diagram 1 consists of only AA and AB

Diagram 2 consists of AA, BB, and AB.

Diagram 3 consists of AA and ABA

Diagram 4 consists of AA and BAB

Thus, only diagram 2 has a mixture of 3 substances.

More on mixtures can be found here: brainly.com/question/6594631

4 0
2 years ago
Determine the freezing point of an aqueous solution containing 10.50 g of magnesium bromide in 200.0 g of water.
Rudiy27
For an aqueous solution of MgBr2, a freezing point depression occurs due to the rules of colligative properties. Since MgBr2 is an ionic compound, it acts a strong electrolyte; thus, dissociating completely in an aqueous solution. For the equation:

                                ΔTf<span> = (K</span>f)(<span>m)(i)
</span>where: 
ΔTf = change in freezing point = (Ti - Tf)
Ti = freezing point of pure water = 0 celsius
Tf = freezing point of water with solute = ?
Kf = freezing point depression constant = 1.86 celsius-kg/mole (for water)
m = molality of solution (mol solute/kg solvent) = ?
i = ions in solution = 3

Computing for molality:
Molar mass of MgBr2 = 184.113 g/mol

m = 10.5g MgBr2 / 184.113/ 0.2 kg water = 0.285 mol/kg


For the problem, 
ΔTf = (Kf)(m)(i) = 1.86(0.285)(3) = 1.59 = Ti - Tf = 0 - Tf

Tf = -1.59 celsius
5 0
3 years ago
Which process releases energy by breaking down glucose and other food molecules in the presence of oxygen?
FinnZ [79.3K]
Cellular respiration

is the process that releases energy by breaking down glucose and other food molecules in the presence of oxygen

5 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r
maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P

Now, the moles of Li3P consumed by 15 g of Al2O3:

n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP

Therefore, the total mass of products is:

m_{products}=13g+8.5g\\\\m_{products}=21.5g

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0
2 years ago
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