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ycow [4]
3 years ago
10

Which of the following equations is NOT balanced properly? Which of the following equations is NOT balanced properly? Cr2(SO4)3

+ 6KOH → 2Cr(OH)3 + 3 K2SO4 2NaHCO3 → Na2CO3 + CO2 + H2O 4NH3 + 14O2 → 4NO2 + 6H2O 2Cr + 6HCl → 2CrCl3 + 3H2 none of the above
Chemistry
1 answer:
tangare [24]3 years ago
7 0

Answer:

Balancing of equation involves making sure the number of atoms of an element on the left hand side(reactant) is equal to the number of atoms of an element on the right hand side(product)

4NH3 + 14O2 → 4NO2 + 6H2O

In the equation above,the number of Oxygen on the left is (14*2)=28 while the number of oxygen on the right is (4*2+6)=14. This makes it an unbalanced equation.

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What is the concentration created when 380.0g of Pb(NO3)2 is added to 330.0 mL of solution?
Juliette [100K]

The concentration of lead nitrate is 3.48 M.

<u>Explanation:</u>

The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,

Here mass of Pb(NO₃)₂ is 380 g

Molar mass of Pb(NO₃)₂ is 331.2 g/mol

Number of moles = $\frac{given mass}{molar mass}

                              =  $ \frac{380 g }{331.2 g/mol}

                              = 1.15 moles

Volume in Litres = 330 ml = 0.33 L

Molarity = $\frac{Moles}{Volume (L)}

          = 3.48 mol/L or 3.48 M

So the concentration of lead nitrate is 3.48 M.

7 0
3 years ago
The Prandtl number, Pr, is a dimensionless group important in heat transfer. It is defined as Pr - Cp*mu/k where Cp is the heat
algol [13]

Answer:

The Prandtl number for this example is 14,553.

Explanation:

The Prandlt number is defined as:

Pr=\frac{C_{p}*\mu}{k}

To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.

\mu=1896 \frac{lbm}{ft*h}*\frac{1000 g}{2.205 lbm}*\frac{3.281 ft}{1 m}*\frac{1h}{3600s}  =7938 \frac{g}{m*s}

Now that we have coherent units, we can calculate Pr

Pr=\frac{C_{p}*\mu}{k}=0.66*7938/0.36=14553

8 0
3 years ago
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