Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
The redox reaction given is,
Cu₍s₎ + 2Ag⁺₍aq₎ ---------> Cu²⁺₍aq₎ + 2Ag₍s₎
The equilibrium constant for this reaction is as follow,
Kc = [Cu²⁺][Ag]² / [Cu][Ag⁺]²
Kc = [Cu²⁺] / [Ag⁺]² ∴ {[Cu₍s₎] = 1 & [Ag₍s₎] = 1
So, Above bolded is <span>the concentration equilibrium constant expression for the given reaction.</span>
The pressure of the gas is 1.0 bar.
<em>pV</em> = <em>nRT</em>
<em>T</em> = (0 + 273.15) K = 273.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (2.0 mol × 0.083 14 bar·L·K⁻¹mol⁻¹ × 273.15 K)/44.8 L = 1.0 bar
D) the outer planets have longer orbital paths than the inner planets
