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3 years ago

In order for a solute to dissolve in a solvent, what must be true?

Chemistry

2 answers:

saw5 [17]3 years ago

8 0

Answer:

In order for a solute to dissolve in a solvent, the attractive forces must be broken.

Explanation:

The rule of solubility says

"Like dissolve Like"

There should be following process in order to dissolve solute into solvent

(1). The particles of solute should be apart.

(2). The solvent particles should move apart to extent so that solute particles should entrapped between solvent particles

(3). The particles of solute and solvent should attract to each others so that they can mix.

Summary:

If new forces arises between the solute and solvent dominate over the forces between the particles of solute, then solute become dissolve into solvent and vice versa.

Minchanka [31]3 years ago

4 0

(1) The attractive forces in a solute need to be broken. (2) The attractive forces in a solute must be decreased. (3) The attractive forces in the solute must be greater than the attractive forces in the solvent. (4) The attractive forces in a solvent must be increased.

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Object A has a molar heat of 31.2 J/mole∙°C and object B molar heat is 11.2 J/mole∙°C. Which object will heat up faster if they

riadik2000 [5.3K]

Answer:

Substance B

Explanation:

Molar heat of A = 31.2J/mole.°C

Molar heat of B = 11.2 J/mole∙°C.

The molar heat of a substance is the amount of heat that must be added to a mole of a substance to raise the temperature by 1°C.

Substance B will heat up faster compared to A.
It has a smaller molar heat compared to A.
This suggests that it will require lesser heat to raise its temperature by 1°C.

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Give the quantum number set for one electron in the 3p sub level of a sulfur (S)

vesna_86 [32]

Answer:- Atomic number for sulfur is 16 and it's electron configuration is $1s^2 2s^2 2p^6 3s^2 3p^4$ . Here, there are total for electrons in 3p and the set of quantum numbers for these 4 electrons would be as..

For the first electron of 3p-

n = 3, l = 1, ml = -1 and ms = +(1/2)

for the second electron of 3p-

n = 3, l = 1, ml = 0 and ms = +(1/2)

for the third electron of 3p-

n = 3, l = 1, ml = +1 and ms = +(1/2)

and for the fourth electron of 3p-

n = 3, l = 1, ml = -1 and ms = -(1/2)

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3 years ago