Answer:
Energy stored at 12 volt will be 115.2 J and energy stored at 24 volt will be 460.8 volt
Explanation:
We have given capacitance of capacitor C = 1.6 F
Normal voltage V = 12 volt
And system uses 2 volt to charge the system
We know that energy stored in the capacitor is equal to 
So energy stored at 12 volt will be equal to 
And energy stored at 24 volt will be equal to 
So energy stored at 12 volt will be 115.2 j and energy stored at 24 volt will be 460.8 j
Answer:
D
Explanation:
HR or human resources, is a division in a company which helps out with recruitment and other human related issues, some including counselling work so I would guess D
Answer:
Explanation:
The resistance column is correct.
I1 = I2 = I3 = I4 = 2 Amps
So all the currents are the same.
R = 110
I = 2 amps
V = ?
Vt = I * R
Vt = 2 * 110
Vt = 220
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V1 = 20 * 2 = 40 volts. That's 40 volts dropped from the right side of R1 to the left side.
V2 = 60 * 2 = 120 volts across the 60 ohm resistor
V3 = 30 * 2 = 60
Total voltage = 40 + 120 + 60
Total voltage = 220 which is just what it should be.
==========================
Power
P1 = V1 * I
P1 = 40 * 2
P1 = 80 watts
P2 = 120*2
P2 = 240
P3 = 60 * 2
P3 = 120
Total Power = 80 + 240 + 120
Total Power = 440
