Answer:
No more information is needed
Explanation:
Radio waves are electromagnetic energy, lower frequency forms of this type of energy that includes light and cosmic rays on the high frequency end that we are able to detect. So in free space (vacuum), radio waves travel at their fastest velocity, the “speed of light”. The reason for the quotation marks is because when light or radio waves are propagating through matter, we observe them traveling more slowly.
Explanation:
We have,
Height of object is 5 cm
Object distance from a convex lens is 18 cm
Focal length of convex lens is 10 cm
i.e. h = 5 cm
u = -18 cm
f = +10 cm
Let v is distance of the image from the lens. Using lens formula :

The magnification of lens is :
, h' is height of the image

h' = -5.00 cm (in three significant figures)
<span>A joule is equal to one watt per second and so we must find out how many seconds are in two hours.
A shortcut you can use is remove the zeros and multiplying the remaining numbers before adding the the zeros back to the total of your result
6 x 6 x 2 = 72 and thus
60 x 60 x 2 = 7200
72 x 15 = 1080 and thus
7200 x 1500 = 10800000 joules
one mega joule equals one million joules
So we can simplify things and say 10.8 MJ</span>
Answer:
a) 1.248 rad/s
b) 13.728 m/s
c) 0.52 rad/s^2
d) 17.132m/s^2
Explanation:
You have that the angles described by a astronaut is given by:

(a) To find the angular velocity of the astronaut you use the derivative og the angle respect to time:
![\omega=\frac{d\theta}{dt}=\frac{d}{dt}[0.260t^2]=0.52t](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B0.260t%5E2%5D%3D0.52t)
Then, you evaluate for t=2.40 s:

(b) The linear velocity is calculated by using the following formula:

r: radius if the trajectory of the astronaut = 11.0m
You replace r and w and obtain:

(c) The tangential acceleration is:

(d) The radial acceleration is:
