Answer:
35 cm
Explanation:
There's a -0.50N force at 20cm.
There's another -0.50N force at 50cm.
You apply a force of F at a position x.
Sum of the forces:
∑F = ma
F − 0.5 N − 0.5 N = 0
F = 1.0 N
Sum of the moments (or torques):
∑τ = Iα
(-0.50 N) (20 cm) + (-0.50 N) (50 cm) + (1.0 N) (x) = 0
x = 35 cm
Answer:
v_f = -25.9 m/s
Explanation:
- The complete question is as follows:
" Assume that a pitcher throws a baseball so that it travels in a straight line parallel to the ground. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. Define the direction the pitcher originally throws the ball as the +x direction.
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x direction. The batter then hits the ball so it goes directly back to the pitcher along the same straight line. What is the ball's velocity just after leaving the bat if the bat applies an impulse of −8.4N⋅s to the baseball?"
Given:
- mass of baseball m = 0.145 kg
- Speed before impact v_i = 32 m/s
- Speed after impact v_f
- Impulse applied by the bat I = - 8.4Ns
Find:
What is the ball's velocity just after leaving the bat
Solution:
- Impulse is the change in linear momentum of the ball according to Newton's second law of motion:
I = m* ( v_f - v_i )
- Taking the + from pitcher to batsman and - from batsman to pitcher.
- Plug in the values:
-8.4 = 0.145* ( v_f - (32) )
v_f = -57.93103 + 32
v_f = -25.9 m/s
Answer:
Friction
Explanation:
This is because friction tends to oppose the motion of an object. Since the unbalance force or net force causes a motion of the object, the frictional force would tend to oppose the object until it is large enough to balance the net force. When this is done, equilibrium is achieved.
At this instance, there is no net force acting on the object.
So, the forces on the object become balanced and in a state of equilibrium.
Answer:
The finger has to be placed at 5.25cm
Explanation:
The steps and appropriate formula in musical instrument is as shown in the attachment.
Answer:
0.5 m
Explanation:
Two charges each of magnitude q
Let the third charge is Q is placed at a distance x from the origin so that the charge is in equilibrium.
The force on Q due to q at origin is balanced by the charge on Q due to the charge q placed at x = 1 m.
So,
1 - x = x
1 = 2x
x = 0.5 m
Thus, the third charge is placed at x = 0.5 m .
