Fk = μK N
N = m a
N = 4 × a
N = 4a
Fk = μK N
17 = 5 × 4a
17 = 20 a
a = ¹⁷/₂₀ = 0.85 m/s²
Answer:
The Balmer series refers to the spectral lines of hydrogen, associated to the emission of photons when an electron in the hydrogen atom jumps from a level
to the level
.
The wavelength associated to each spectral line of the Balmer series is given by:

where
is the Rydberg constant for hydrogen, and where
is the initial level of the electron that jumps to the level n = 2.
The first few spectral lines associated to this series are withing the visible part of the electromagnetic spectrum, and their wavelengths are:
656 nm (red, corresponding to the transition
)
486 nm (green,
)
434 nm (blue,
)
410 nm (violet,
)
All the following lines lie in the ultraviolet part of the spectrum. The limit of the Balmer series, corresponding to the transition
, is at 364.6 nm.
Answer:
The wavelength of a wave with the frequency of 330hz and a speed of 343m/s would be 1.04m
Explanation:
You can get the wavelength of a wave by dividing the speed of the wave by its frequency, which in this case would be:
343/300, which as a decimal number, it'd be 1.04.
I hope I helped you, and a "Brainliest" is always appreciated! ☺
Answer:
the power in both cases is the same.
Explanation:
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